Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
The month of January has 31 days, so from January 1st to February 14th, there are 31 + 14 or 45 days, namely x = 45.
y = 3.06 * sin[ 0.017(45) - 1.40 ] + 12.23.
make sure your calculator is in Degree mode.
Answer:
The larger number is 96.
Step-by-step explanation:

Answer:
Nicholas bought 1.8 lbs, and Jane bought 3lbs.
Step-by-step explanation:
Divide the total amount by how much it is per pound, so 8.10 divided by 4.50 = 1.8 and 9.75 divided by 3.25= 3