If the density of lead is 11.342 what would be the volume of a 200.0 g sample of metal

What creates a thermocline?

vredina [299]

Answer:

here are the answers to all the questions on the quiz Phytoplankton

There would be no ocean life without _____.

thermocline

marine snow

phytoplankton

runoff

Phytoplankton is the answer.

What creates a thermocline?

a series of strong ocean storms

a difference in water temperature

a difference in the amount of phytoplankton

a change in the phytoplankton population

a difference in water temperature is the answer

What limits the growth of phytoplankton?

It is limited by the amount of water that runs off into the ocean.

It is limited by the number of fish eating the phytoplankton directly.

It is limited by the depth of the water in the ocean.

It is limited by the amount of nutrients in the water.

It is limited by the amount of nutrients in the water is the answer

What are phytoplankton? (Select all that apply.)

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

They are small plants and animals that exist both on land and in the ocean.

They are microscopic animals that drift with the currents of the wind.

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

are the answers

Which is a possible food chain in the ocean from start to finish?

phytoplankton, zooplankton, small fish, large fish, large shark

zooplankton, phytoplankton, large fish, small fish, large shark

phytoplankton, large shark, zooplankton, large fish, small fish

large shark, large fish, small fish, zooplankton, phytoplankton

phytoplankton, zooplankton, small fish, large fish, large shark is the answer

Hope this helps!

did the quiz and got 100%

May I get braineist pls

6 0

2 years ago

How many grams of CaCl2 are needed to make 277.8g of a solution that is 31.5% (m/m) in water? Note that mass is not technically

Sveta_85 [38]

Answer: The mass of calcium chloride present in given amount of solution is 87.5 g

Explanation:

We are given:

Mass of solution = 277.8 grams

Also, 31.5 % (m/m) of calcium chloride in water. This means that 31.5 g of calcium chloride is present in 100 g of solution.

To calculate the mass of calcium chloride in the given amount of solution, we use unitary method:

in 100 g of solution, the mass of calcium chloride present is 31.5 g

So, 277.8 g of solution, the mass of calcium chloride present is $\frac{31.5}{100}\times 277.8=87.5g$

Hence, the mass of calcium chloride present in given amount of solution is 87.5 g

8 0

3 years ago

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago

Copper has two naturally occurring isotopes. Cu−63 has a mass of 62.939 amu and relative abundance of 69.17%.

fiasKO [112]

The answer is 64.907 amu.

The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
atomic mass of copper = atomic mass of isotope 1 * abundance 1 + atomic mass of isotope 2 * abundance 2

We know:
atomic mass of copper = 63.546 amu
The atomic mass of isotope 1 is: 62.939 amu
The abundance of isotope 1 is: 69.17% = 0.6917
The atomic mass of isotope 1 is: x
The abundance of isotope 2: 100% - 69.17% = 30.83% = 0.3083

Thus:
63.546 amu = 62.939 amu * 0.6917 + x * 0.3083
63.546 amu = 43.535 amu + 0.3083x
⇒ 63.546 amu - 43.535 amu = 0.3083x
⇒ 20.011 amu = 0.3083x
⇒ x = 20.011 amu ÷ 0.3083 = 64.907 amu

7 0

3 years ago

What two categorical ways of thinking about matter are discussed in the passage?

Mamont248 [21]

Answer:

There's no passage but I can say that matter are that ''thing'' which extend through all Universe, matter is everything. It can be seen or felt as liquid, gas or solid. This changes of its state depend on the amount of energy that is involved.

So, here is used categorical thinking because is a abstract concept that is hard to understand sometimes. It's abstract when we say that matter is all, not just what we see, but even what we don't see like ''Dark Matter'', which is the majority in the Universe.

4 0

3 years ago