Answer:
concentration in ppm of DDT = 0.011 ppm
Explanation:
since ppm of DDT =mg of DDT /Kg of solution ( or μg of DDT /g of solution) , then
concentration in ppm of DDT = 4.21 × 10⁻⁷ kg * 10⁶ mg/kg / ( 1.00 g/mL * 3.7 L * 1000 ml/L * 1 kg/1000gr) = 0.011 ppm
then
concentration in ppm of DDT = 0.011 ppm
When conc. H2SO4comes in contact with sugar, it becomes black due to dehydration
What is the actual yield of a reaction?
A. The calculated amount of product
B. The fractional amount of product
C. The predicted amount of product
D. The measured amount of product
D