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Brrunno [24]
3 years ago
11

What is the name of the molecular compound SF 5? sulfur pentafluoride sulfur hexafluoride sulfur heptafluoride monosulfur tetraf

luoride none of the above
Chemistry
1 answer:
romanna [79]3 years ago
4 0

Answer: sulfur pentafluoride

Explanation:

The rules for naming of binary molecular compound :

In the given formula, the lower group number element is written first in the name and keep its element name and the higher group number is written second.

First element i.e. sulphur in the formula is named first and keep its element name.

1) Gets a prefix if there is a subscript on it such as mono for 1, di for 2, tri for 3 and so on.

Second element i.e. fluorine is named second.

1) Use the root of the element name, if it is an anion then use suffix (-ide).

2) Always use a prefix on the second element such as mono for 1, di for 2, tri for 3 and so on.

Therefore, the chemical name of compound SF_5 is sulfur pentafluoride

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Which compounds can be made with the reaction benzene via electrophilic aromatic substitution using isopropyl chloride and AlCl3
Hitman42 [59]

Answer:

isopropyl benzene (cumene)

Explanation:

The reaction of isopropyl chloride and AlCl3 and benzene belongs to the class of organic reactions known as the Friedel Kraft alkylation.

The mechanism of the reaction involves the formation of a tetrahedral complex [AlCl4]^-.

The electrophile now is the isopropyl group which attacks the benzene to yield the product.

4 0
2 years ago
When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is r
butalik [34]

Answer:

There is 78.25g NaHCO3 required

Explanation:

Step 1: Balance the equation

2 NaHCO3 → Na2CO3 + CO2 + H20

For 2 moles of NaHCO3 consumed, there is produced 1 mole of Na2CO3, 1 mole of CO2 and 1 mole of H2O.

Step 2: calculating moles of CO2

mass of Co2 = 20.5g

Molar mass of CO2 = 44.01 g/mole

moles of CO2 = 20.5 / 44.01 = 0.4658 moles

Step 3: Calculating moles of NaHCO3

Since we have for 1 mole CO2 produced, there is 2 moles of NaHCO3 consumed.

To calculate number of moles of NaHCO3, we have to multiply the number of moles of CO2, by 2.

⇒ 0.4658 x2 = 0.9316 moles

Step 4: Calculating the mass of NaHCO3

mass of NaHCO3 = moles of NaHCO3 x Molar mass of NaHCO3

mass = 0.9316 moles x 84g/ mole = 78.25g NaHCO3

There is 78.25g NaHCO3 required

4 0
3 years ago
To sum up the question: why are some parts of the body more sensitive than others?
natulia [17]

Answer:

Some areas of the body are more sensitive than others because they have more nerve endings. It hurts when you bite your tongue because the sides of your tongue have a lot of nerve endings that are very sensitive to pain! The tongue, lips, and fingertips are the most touch-sensitive parts of the body.  The parts of your skin that need to be most sensitive like your fingertips and your lips have more receptor cells in them than others less sensitive areas.  The least sensitive skin on the human body is found in the heel area. This is because there are very few nerves in the heel to feel things. If there were too many nerves in our heels then walking would be far too painful.

Explanation:

5 0
3 years ago
Read 2 more answers
How many elements have scientists discovered​
Luda [366]

Answer:

118

Explanation:

The discovery of the 118 chemical element known to exist us of 2021

5 0
3 years ago
What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not
Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 =  [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

7 0
3 years ago
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