1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nady [450]
3 years ago
5

Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell

Chemistry
2 answers:
serious [3.7K]3 years ago
7 0

Answer: 2.5 moles of Mg+2

Since it is an example for intermolecular redox reaction. Here Mg gets oxidized to Mg+2 and Zn+2 gets reduced to Zn.

Mg(s)+ Zn+2(aq) -------> Mg+2(aq) + Zn(s)

From the balanced equation, 1:1 molar ratio of Mg and Zn+2. Hence 2.5 moles of Zn+2 produce 2.5 moles of Mg+2.

Montano1993 [528]3 years ago
4 0
The question is incomplete. Complete question is attached below.

Solution:
The reaction involved in present electrochemical cell is:

Mg(s)     +       Zn2+(aq.)      ↔        Zn(s)      +      Mg2+ (aq.)

Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.

Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>

You might be interested in
A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th
grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization =  37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0
2 years ago
I'm confused
aleksley [76]

Answer:

Energy

Explanation:

Between gas to liquid, or liquid to gas, will give off extra energy to the surrounding environment

4 0
1 year ago
Read 2 more answers
How does the number of atoms in one mole of argon compare with the number of molecules in one mole of ammonia
AfilCa [17]
They are the same because the definition of a mole is 6.022 x 10^23 molecules or atoms based on whether it is a molecule or element. so there are 6.022 x 10^23 atoms of argon in one mole of argon and 6.022 x 10^23 molecules of ammonia in one mole of ammonia
5 0
2 years ago
After the recycled plastic is released from the machine into the brick mold, explain what will happen to the kinetic energy in t
Rina8888 [55]

Answer: Depending on the data and the patterns, sometimes we can see that pattern in a simple tabular presentation of the data. Other times, it helps to visualize the data in a chart, like a time series, line graph, or scatter plot.

Explanation:

1960 5.91

1970 5.59

1980 4.83

1990 4.05

2000 3.31

2010 2.60

8 0
2 years ago
Help pleasee I need help to write the formulas i’m so lost
pishuonlain [190]

Answer:

NH4

Explanation:

3 0
2 years ago
Other questions:
  • Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
    5·1 answer
  • A 240g hydrated sodium sulphide contains 162g of water of crystallisation. What is the correct molecular formula for this compou
    7·1 answer
  • Help me plsssssssss Brainliest to correct answer
    10·1 answer
  • Identify the single displacement reaction. C4H12 + 7O2 ⟶ 6H2O + 4CO2 2H2 + O2 ⟶ 2H2O Al2S3 ⟶ 2Al + 3S Cl2 + 2KBr ⟶ 2KCl + Br2
    8·1 answer
  • Which of the following statements about gases is false?
    12·1 answer
  • Which of the following best explains why you sanded the copper wire before burning it? to create less friction between the coppe
    15·1 answer
  • A molecule composed of atoms is called _________.
    15·2 answers
  • Beth is designing a business card
    6·2 answers
  • What is Science?
    11·2 answers
  • What volume of 0.555M KNO3 solution would contain 12.5 g of solute
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!