Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell
2 answers:
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Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>
Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>
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Considering the definition of molarity, the molar concentration is 0.294 .
Molarity reflects the concentration of a solution indicating the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units .
In this case, you know:
- amount of moles of solute= 0.250 moles
- volume= 0.850 L
Replacing in the definition of molarity:
Solving:
molarity= 0.294
Finally, the molar concentration is 0.294 .
Learn more about molarity with this example: brainly.com/question/15406534?referrer=searchResults