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3 years ago

Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell

Chemistry

2 answers:

serious [3.7K]3 years ago

7 0

Answer: 2.5 moles of Mg+2

Since it is an example for intermolecular redox reaction. Here Mg gets oxidized to Mg+2 and Zn+2 gets reduced to Zn.

Mg(s)+ Zn+2(aq) -------> Mg+2(aq) + Zn(s)

From the balanced equation, 1:1 molar ratio of Mg and Zn+2. Hence 2.5 moles of Zn+2 produce 2.5 moles of Mg+2.

Montano1993 [528]3 years ago

4 0

The question is incomplete. Complete question is attached below.

Solution:
The reaction involved in present electrochemical cell is:

Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)

Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.

Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>

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Give five properties of water.

Gelneren [198K]

Polarity, cohesion, adhesion, surface tension, high specific heat, and evaporating cooling

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2 years ago

Read 2 more answers

Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 °C? (HINT: the act

algol13

Answer:

D) 2.3 x 10⁻¹ s⁻¹

Explanation:

The rate constant is related to the activation energy through the formula:

k= Ae^(-Eₐ /RT)

where A is the collision factor, Eₐ the activation energy, R is the gas constant ( 8.314 J/Kmol ) , and T is the temperature (K)

So a plot of lnk versus 1/T ( Arrehenius plot ) gives us a straight line with slope equal -Eₐ/R and intercept lnA

lnk = -(Eₐ/T)(1/T) + lnA

which has the form y= mx + b

In this problem, we can use the data provided to:

a) Using a calculator determine the slope and intercept and then calculate the value of rate constant at 320 ºC, or

b) Plot the data and determine the equation of the best line , and answer the question for k @ 320 ºC by reading the value from the plot.

Once you do the plot, the resulting equation is:

y = - 19 x 10³ x + 30,582 ( R² = 0.999 )

So for T = 320 + 273 K = 593 K

Y = 19 x 10³ X + 30.58

So for T = (320 + 273)K = 593 K

Y = -19 x 10³ ( 1/593) + 30.58 = -32.04 +30.58 = - 1.46

and then since

y = lnk ⇒ e^y = k

k= e^-1.46 = 2.3 x 10⁻¹ s⁻¹

Note: there is an error of transcription in the value for T = 472.1 ( 1/T = 2.118 x 10⁻³ and not 2.228 x 10⁻³). You can recognize this mistake if you plot the data and notice it produces an outlier.

5 0

3 years ago

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

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3 years ago

What is the density of a cube that has a mass of 25 g in a volume of 125 cm 3

GalinKa [24]

<span>The density of an object is defined to be its mass divided by the volume it occupies. For this problem, the mass of the cube was given to be 25 g while its volume is 125 cm</span>³. Thus, we simply divide 25 g by 125 cm³ to get the object’s density. We then calculate that the cube has a density of 0.2 g/ cm³.

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3 years ago

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AleksAgata [21]

Answer:

$\delta=101.13 g/cm^3$