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Nady [450]
3 years ago
5

Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell

Chemistry
2 answers:
serious [3.7K]3 years ago
7 0

Answer: 2.5 moles of Mg+2

Since it is an example for intermolecular redox reaction. Here Mg gets oxidized to Mg+2 and Zn+2 gets reduced to Zn.

Mg(s)+ Zn+2(aq) -------> Mg+2(aq) + Zn(s)

From the balanced equation, 1:1 molar ratio of Mg and Zn+2. Hence 2.5 moles of Zn+2 produce 2.5 moles of Mg+2.

Montano1993 [528]3 years ago
4 0
The question is incomplete. Complete question is attached below.

Solution:
The reaction involved in present electrochemical cell is:

Mg(s)     +       Zn2+(aq.)      ↔        Zn(s)      +      Mg2+ (aq.)

Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.

Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>

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Explanation:Sucrose is dissacharides an organic compound in the class of carbonhydrate with the chemical formula C11H22O11.molar concentration is given by number of moles/Volume,this implies that moles=molar concentration ×Volume=0.130M×2.75L=0.3575moles.

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So mass =moles ×molecular mass=0.3575moles×352g/moles=125.84g

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