Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell
2 answers:
The question is incomplete. Complete question is attached below.
Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>
Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>
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Explanation:
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i.e. 22.4 L
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