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jasenka [17]
3 years ago
11

How to find percentage abundanace

Chemistry
1 answer:
Ghella [55]3 years ago
5 0

Answer and Explanation:

How to Calculate the Percent Abundance of an Isotope

Step 1: Find the Average Atomic Mass. Identify the atomic mass of the element from your isotopic abundance problem on the periodic table. ...

Step 2: Set Up the Relative Abundance Problem. ...

Step 3: Solve for x to Get the Relative Abundance of the Unknown Isotope. ...        

 Step 4: Find percent abundance.

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Inessa05 [86]

Answer:

Yes, Is a glass window good reflector of heat.

4 0
3 years ago
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The equilibrium: 2 NO2(g) \Longleftrightarrow⇔ N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar
Sergeeva-Olga [200]

Answer:

  • Initial: forward rate > reverse rate
  • Equilibrium: forward rate = reverse rate

Explanation:

2NO₂(g) → N₂O₄(g)   Kc=4.7

The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

7 0
3 years ago
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
The potential energy diagram shows the gain and loss of potential energy as water molecules decompose into hydrogen and oxygen.
Dovator [93]

Answer:

  • The<em> diagram</em> with the five<em> labels</em> of the parts is in the image attached. Please, see the image.

Explanation:

<u>1) General explanation:</u> a <em>potential chemical energy diagram</em> is used to show how the <em>reactants</em> gain energy until they reach the <em>activation energy</em>, form the <em>activated complex</em>, and release part of the energy to form the <em>products</em>.

The difference between the chemical potential energy of the products and the reactants is the <em>enthalpy of the reaction</em>:

  • ΔH rxn = ΔH products - ΔH reactants.

The labels that correspond to each part of the diagram are explained next.

<em><u>2) Reactants:</u></em>

This is the substances at the start, so they appear on the left bottom side of the diagram.

<em><u>3) Activation energy:</u></em>

It is the energy that the reactants must reach (the highest point) in order to the reaction occurs.

<u><em>4) Activated complex:</em></u>

This is the intermediate state and of highest energy. The reactants have formed a complex at mid way between the reactants and the products.

<u><em>5) Products:</em></u>

These are the substances formed when the reaction is completed. They are lower in energy than the activated complex. They can be either higher or lower in energy than the reactants. The products are shown to the right of the diagram.

<em><u>6) Enthalpy of the reaction:</u></em>

The enthalpy of the reaction is the difference in energy of the products and the reactants. In this case, since, the products are higher in energy, it means that the reaction absorbed energy and it is an endothermic reaction.

4 0
3 years ago
I need help with this
cricket20 [7]

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Explanation:

7 0
2 years ago
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