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Oliga [24]
3 years ago
12

At stp which gas will diffuse more readily than ne

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
5 0
Hello!

I believe the gas that will diffuse more readily than neon is: Helium.

pav-90 [236]3 years ago
4 0
I am assuming you are talking about Neon. The rate of diffusion is directly proportional to the molar mass of the gas. Since neon has a molar mass of 20.18 grams, the gas must have a lower molar mass and must be a gas at 273 Kelvin. There are several elements that fulfill this criteria: Hydrogen, Helium, Oxygen, Nitrogen, and Fluorine. 
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Dimas [21]
You can go to a website about that it will give you the answers
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3 years ago
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Which is not a compound? water silicon dioxide oxygen gas carbon dioxide gas
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All of these are compounds except oxygen because a compound is two or more different elements bonded together.
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How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=200 K

Putting value in the given equation:

\frac{nRT}{P} =V

V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}

V= 1.1214 mL

Learn more about the ideal gas here:

brainly.com/question/27691721

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4 0
2 years ago
How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Dmitriy789 [7]

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

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Elena L [17]
I think is D A have a nice day
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