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STALIN [3.7K]
3 years ago
12

In the simple cubic unit cell, the centers of ____________ identical particles define the ____________ of a cube. The particles

do touch along the cube's ____________ but do not touch along the cube's ____________ or through the center. There is/are ____________ particle per unit cell and the coordination number is ____________ .
Chemistry
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

in the simple cubic unit cell, the centers of ____Eight________ identical particles define the ____corners________ of a cube. The particles do touch along the cube's _____edges _______ but do not touch along the cube's ___ diagonally_________ or through the center. There is/are __eight__________ particle per unit cell and the coordination number is _____six_______ .

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3 years ago
An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having
dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass  2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007  (1-x) = 1.008  

2.014x + 1.007  - 1.007 x = 1.008  

2.014x - 1.007x  =  1.008  -  1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass  2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

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3 years ago
Unsur senyawa CaCO3 adalah
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