Question

Iron reacts with cl2 according to the equation 2 fe(s) + 3 cl2(g) ? 2 fecl3(s). how many moles of cl2 is needed to react with 4.4 mol fe?

Answer 1

2Fe + 3Cl₂ ---> 2FeCl₃

4.4mol of Fe, you have a 2:3 ratio of Fe to Cl₂ so divide 4.4/2 = 2.2 and multiply by three 2.2 x 3 = 6.6mol of Cl₂

hope that helps :)

Answer 2

Answer: The amount of chlorine gas needed to react are 6.6 moles.

Explanation:

We are given:

Moles of iron = 4.4 moles

For the given chemical equation:

$2Fe(s)+3Cl_2(g)\rightarrow 2FeCl_3(s)$

By Stoichiometry of the reaction:

2 moles of iron reacts with 3 moles of chlorine gas

So, 4.4 moles of iron will react with = $\frac{3}{2}\times 4.4=6.6mol$ of chlorine gas

Hence, the amount of chlorine gas needed to react are 6.6 moles.