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gulaghasi [49]
3 years ago
15

Iron reacts with cl2 according to the equation 2 fe(s) + 3 cl2(g) ? 2 fecl3(s). how many moles of cl2 is needed to react with 4.

4 mol fe?
Chemistry
2 answers:
IceJOKER [234]3 years ago
8 0
2Fe + 3Cl₂ ---> 2FeCl₃

4.4mol of Fe, you have a 2:3 ratio of Fe to Cl₂ so divide 4.4/2 = 2.2 and multiply by three 2.2 x 3 = 6.6mol of Cl₂

hope that helps :)
anyanavicka [17]3 years ago
5 0

<u>Answer:</u> The amount of chlorine gas needed to react are 6.6 moles.

<u>Explanation:</u>

We are given:

Moles of iron = 4.4 moles

For the given chemical equation:

2Fe(s)+3Cl_2(g)\rightarrow 2FeCl_3(s)

By Stoichiometry of the reaction:

2 moles of iron reacts with 3 moles of chlorine gas

So, 4.4 moles of iron will react with = \frac{3}{2}\times 4.4=6.6mol of chlorine gas

Hence, the amount of chlorine gas needed to react are 6.6 moles.

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1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.
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Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

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