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Lyrx [107]
3 years ago
12

Write a method that could be used to produce pure crystals of copper chloride from copper oxide and hydrochloric acid.

Chemistry
1 answer:
joja [24]3 years ago
3 0

- Describe how you would make the salt from the reactants.

CuO + 2 HCl → CuCl₂ + H₂O

- Describe how you would purify the salt from the reaction mixture.

Filter the solution and let the product crystallize.

Explanation:

The reaction between copper oxide (CuO) and hydrochloric acid (HCl) will produce copper chloride (CuCl₂) and water:

CuO + 2 HCl → CuCl₂ + H₂O

-Describe how you would make the salt from the reactants

In a beaker which contain cooper oxide add the hydrochloric acid. To avoid working with concentrated hydrochloric acid, the acid may be diluted with water but make sure the add the stoechiometric amount (and a little bit of excess) in respect with the copper oxide.

-Describe how you would purify the salt from the reaction mixture.

Let the reaction proceed and then filter the solution to remove the unreacted cooper oxide.

Let the filtered solution, which contain copper chloride, water and unreacted hydrochloric acid, to stand undisturbed for several days. You may see the crystals growing from the solution. To speed up the process you may reduce the temperature.

Learn more about:

purifying compounds

brainly.com/question/5586971

brainly.com/question/4757187

#learnwithBrainly

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Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i
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The composition in mol% of the elements are :

  • 4.91%  of Al₂O₃ in alloy  
  • 95.08% of Cu in alloy

<u>Given data : </u>

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

<u />

<u>First step : calculate the mole of elements</u>

i) moles of Al₂O₃ in alloy

 = mass of Al₂O₃  in alloy /  Atomic mass of Al₂O₃

 = 7.7 gm  / 102 gm/mol

 = 0.075 mol

ii) moles of Cu in alloy

 = mass of Cu in alloy / Atomic mass of Cu

 = 92.3 gm / 63.5 gm/mol

 = 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

<u>Next step : Determine the mole </u><u>percentages </u>

i) Mole percentage of Al₂O₃ in alloy  

= ( 0.075 ) / 1.525  * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

<u />

Hence we can conclude that The composition in mol% of the elements are : 4.91%  of Al₂O₃ in alloy and  95.08% of Cu in alloy.

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