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4 years ago

Write a method that could be used to produce pure crystals of copper chloride from copper oxide and hydrochloric acid.

Chemistry

1 answer:

joja [24]4 years ago

3 0

- Describe how you would make the salt from the reactants.

CuO + 2 HCl → CuCl₂ + H₂O

- Describe how you would purify the salt from the reaction mixture.

Filter the solution and let the product crystallize.

Explanation:

The reaction between copper oxide (CuO) and hydrochloric acid (HCl) will produce copper chloride (CuCl₂) and water:

CuO + 2 HCl → CuCl₂ + H₂O

-Describe how you would make the salt from the reactants

In a beaker which contain cooper oxide add the hydrochloric acid. To avoid working with concentrated hydrochloric acid, the acid may be diluted with water but make sure the add the stoechiometric amount (and a little bit of excess) in respect with the copper oxide.

-Describe how you would purify the salt from the reaction mixture.

Let the reaction proceed and then filter the solution to remove the unreacted cooper oxide.

Let the filtered solution, which contain copper chloride, water and unreacted hydrochloric acid, to stand undisturbed for several days. You may see the crystals growing from the solution. To speed up the process you may reduce the temperature.

Learn more about:

purifying compounds

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Aneli [31]

The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
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Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
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