Answer:
Titration
Explanation:
The best technique which can be used to determine the number of moles of the HCl in the sample is titration.
The given amount of HCl solution must be titrated with known concentration of the base like NaOH.
The volume of NaOH required must be noted also.
According to the reaction,

At equivalence point
Moles of
= Moles of 
Considering:-
Moles of 
Thus, in this way, moles of HCl can be determined.
Answer: The concentration of the OH-, CB = 0.473 M.
Explanation:
The balanced equation of reaction is:
2HCl + Ca(OH)2 ===> CaCl2 + 2H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 2 (from the balanced equation of reaction)
NB is the number of mole of base = 1 (from the balanced equation of reaction)
CA is the concentration of acid = 1M
CB is the concentration of base = to be calculated
VA is the volume of acid = 23.65 ml
VB is the volume of base = 25mL
Substituting
1×23.65/CB×25 = 2/1
Therefore CB =1×23.65×1/25×2
CB = 0.473 M.
Answer:
9
Explanation:
14-5.=pOH
- Hope that helps! Please let me know if you need further explanation.
Crystalline silica is hazardous when small particles are
inhaled. They can penetrate deep into the lungs and cause disabling and
sometimes fatal lung diseases including silicosis, lung cancer and kidney
disease. The particles of crystalline silica enters the lungs and causes the
formation of scar tissue known as silicosis, thus reducing the lungs’ ability
to take in oxygen.
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
We want to standardize a H₂SO₄ solution with NaOH. The neutralization reaction is:
H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + H₂O
The buret, which contains NaOH, reads initially 0.63 mL, and 44.73 mL at the endpoint. The used volume of NaOH is:

44.10 mL of 0.450 M NaOH are used for the titration. The reacting moles of NaOH are:

The molar ratio of H₂SO₄ to NaOH is 1:2. The moles of H₂SO₄ that react with 0.0198 moles of NaOH are:

0.00990 moles of H₂SO₄ are in 20.00 mL of solution. The molarity of H₂SO₄ is:
![[H_2SO_4] = \frac{0.00990mol}{0.02000} = 0.495 M](https://tex.z-dn.net/?f=%5BH_2SO_4%5D%20%3D%20%5Cfrac%7B0.00990mol%7D%7B0.02000%7D%20%3D%200.495%20M)
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
Learn more: brainly.com/question/2728613