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3 years ago

Alkali metals are relatively soft because the atoms contribute only one _____ to a metallic bond

1 answer:

7 0

Valence Electron because the more valence electrons an atom can contribute the shared pool, the stronger the metallic bonds will be

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Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissol

Stells [14]

Here is the complete question.

Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits

Answer:

0.9567 mol

Explanation:

Given that:

mass of glycerol = 1.61 g

molar mass of glycerol = 92.1 g/mol

no of mole = $\frac{mass}{molar mass}$

∴ number of moles of glycerol ( $n_{glycerol}$ ) = $\frac{1.61}{92.1}$

= 0.0175 mol

Volume of ethanol = 22.60 mL

Density of ethanol = 0.7893 g/mL

Since Density = $\frac{mass}{volume}$

∴ mass of ethanol = density of ethanol × volume of ethanol

mass of ethanol = 0.7893 g/mL × 22.60 mL

mass of ethanol = 17.838 g

Number of moles of ethanol $(n_{ethanol})$ = $\frac{17.838}{46.0684}$

= 0.387 mole

∴ the mole fraction of the solvent can be determined as:

$X_{solvent} = X_{ethanol} =$ $\frac{n_{ethanol}}{n_{glycerol}+n_{ethanol}}$

$=\frac{0.387 mol}{(0.0175+0.387)mol}$

$= \frac{0.387mol}{0.4045mol}$

= 0.95673671199

≅ 0.9567 mol

∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol

7 0

3 years ago

Which of the following is the best definition of an independent variable

Soloha48 [4]

Answer:

that one

Explanation:

<h2>esssszzzzjijfc</h2>

8 0

3 years ago

A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL

d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 0.70

Putting values in above equation, we get:

$0.70=-\log[H^+]$

$[H^+]=10^{-0.70}=0.199M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated nitric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted nitric acid solution

We are given:

$M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL$

Putting values in above equation, we get:

$7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL$

Hence, the volume of concentrated solution required is 9.95 mL

6 0

2 years ago

URGENT!!! What is the balanced form of this equation?

Ostrovityanka [42]

Explanation: This is a reaction of oxidation of $H_2O_2$ in the presence of acidified $KMnO_4$ . Acidified $KMnO_4$ is a strong oxidizing agent.

To balance out the $H^+$ on the reactant side, we write $H_2O$ on the product side.

Balancing out the following reaction gives us:

$2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2$

5 0

3 years ago

The reducing agent in the reaction described in Fe + 2HCl → FeCl2 + H2 is A. H2. B. Fe. C. HCl. D. FeCl2.

Fed [463]

The reducing agent is b). Fe

7 0

3 years ago

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