Answer:
![y=-\frac{5}{3} x-\frac{42}{5}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B3%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
Step-by-step explanation:
Given the slope and another point, simply plug them into the point-slope formula to find your y-intercept.
![y-y1=m(x-x1)\\y-(-6)=\frac{3}{5} (x-4)\\y+6=\frac{3}{5} x-\frac{12}{5} \\y=\frac{3}{5} x-\frac{42}{5}](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29%5C%5Cy-%28-6%29%3D%5Cfrac%7B3%7D%7B5%7D%20%28x-4%29%5C%5Cy%2B6%3D%5Cfrac%7B3%7D%7B5%7D%20x-%5Cfrac%7B12%7D%7B5%7D%20%5C%5Cy%3D%5Cfrac%7B3%7D%7B5%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
Now that we've found your y-intercept, we have the original equation. To find the perpendicular equation, you need the opposite reciprocal of your slope.
To find the 'opposite,' change your slope's sign. Since your slope is positive
, the opposite is
.
To find the 'reciprocal,' flip your fraction. This will make your slope
.
Your final equation is:
![y=-\frac{5}{3} x-\frac{42}{5}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B3%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
Answer:
(a) The future value after 9 years is $7142.49.
(b) The effective rate is
.
(c) The time to reach $13,000 is 21.88 years.
Step-by-step explanation:
The definition of Continuous Compounding is
If a deposit of
dollars is invested at a rate of interest
compounded continuously for
years, the compound amount is
![A=Pe^{rt}](https://tex.z-dn.net/?f=A%3DPe%5E%7Brt%7D)
(a) From the information given
![P=4700](https://tex.z-dn.net/?f=P%3D4700)
![r=4.65\%=\frac{4.65}{100} =0.0465](https://tex.z-dn.net/?f=r%3D4.65%5C%25%3D%5Cfrac%7B4.65%7D%7B100%7D%20%3D0.0465)
![t=9 \:years](https://tex.z-dn.net/?f=t%3D9%20%5C%3Ayears)
Applying the above formula we get that
![A=4700e^{0.0465\cdot 9}\\A=7142.49](https://tex.z-dn.net/?f=A%3D4700e%5E%7B0.0465%5Ccdot%209%7D%5C%5CA%3D7142.49)
The future value after 9 years is $7142.49.
(b) The effective rate is given by
![r_E=e^r-1](https://tex.z-dn.net/?f=r_E%3De%5Er-1)
Therefore,
![r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}](https://tex.z-dn.net/?f=r_E%3De%5E%7B0.0465%7D-1%3D0.04759%5C%5Cr_E%3D4.759%20%5C%3A%7B%5C%25%7D)
(c) To find the time to reach $13,000, we must solve the equation
![13000=4700e^{0.0465\cdot t}](https://tex.z-dn.net/?f=13000%3D4700e%5E%7B0.0465%5Ccdot%20t%7D)
![4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88](https://tex.z-dn.net/?f=4700e%5E%7B0.0465t%7D%3D13000%5C%5C%5C%5C%5Cfrac%7B4700e%5E%7B0.0465t%7D%7D%7B4700%7D%3D%5Cfrac%7B13000%7D%7B4700%7D%5C%5C%5C%5Ce%5E%7B0.0465t%7D%3D%5Cfrac%7B130%7D%7B47%7D%5C%5C%5C%5C%5Cln%20%5Cleft%28e%5E%7B0.0465t%7D%5Cright%29%3D%5Cln%20%5Cleft%28%5Cfrac%7B130%7D%7B47%7D%5Cright%29%5C%5C%5C%5C0.0465t%5Cln%20%5Cleft%28e%5Cright%29%3D%5Cln%20%5Cleft%28%5Cfrac%7B130%7D%7B47%7D%5Cright%29%5C%5C%5C%5C0.0465t%3D%5Cln%20%5Cleft%28%5Cfrac%7B130%7D%7B47%7D%5Cright%29%5C%5C%5C%5Ct%3D%5Cfrac%7B%5Cln%20%5Cleft%28%5Cfrac%7B130%7D%7B47%7D%5Cright%29%7D%7B0.0465%7D%5Capprox21.88)
Yes, it is. if you end up getting 4.85239854285696357835482938339158989............................... you wouldn't want to measure out exactly that much.
Answer:
The answer is Evelyns is winning the game because he is clearly up ahead
Step-by-step explanation:
Hope I helped I wish the best for you