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mariarad [96]
3 years ago
14

Explain how you can compare the size of a product to the size of a factor when multiplying fractions without actually doing mult

iplication including model
Mathematics
1 answer:
MAXImum [283]3 years ago
5 0
Answer: If you multiply a number by a fraction less than 1, the resulting product will be smaller than the original fraction.

Imagine, if you had half a pizza and you ate one-half of that. You would multiply 1/2 by 1/2 and get an even smaller number. The result would be 1/4.

On the other hand, if you multiply a number by a mixed number that is larger than one, the result would be larger than when you started.
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Plz help i will mark you brainlist this is due in 5 minutes
pshichka [43]

Answer: -10 degress is colder than -4

so the answer will be: C (-10 < -4)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I don’t understand none of this math
Ivan

Answer:

6

Step-by-step explanation:

(a^3 - b^3)/5

Let a =2 and b = -3

(2^3 -  (-3)^3)/5

Exponents inside the parentheses

(8 - -27)/5

Subtracting a negative is like adding

(8+27)/5

Finish adding inside the parentheses

35/5

Divide

7

4 0
3 years ago
Read 2 more answers
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
Tamara says that raising the number i to any integer power results in either -1 or 1 as the result, since i^2 = -1. Do you agree
Roman55 [17]
I agree only if you have even powers -- even negative ones.

1/i^2 = 1/-1 = - 1
i^0 also gives 1 So far no problem.

It is when you consider the odd numbers that you don't get 1 or -1 
You get either -i or i
i^(4n + 1) =  i
i^(4n - 1) = -i

5 0
3 years ago
When 6r − 17r = -66 is solved, the result is: A. 6 B. -6 C. -11 D. 11
Anna71 [15]

Answer:

A

Step-by-step explanation:

6r - 17r = -66

Subtract like terms.

-11r = -66

Divide both sides by -11.

r = -66/-11

r = 6

4 0
3 years ago
Read 2 more answers
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