Tamara says that raising the number i to any integer power results in either -1 or 1 as the result, since i^2 = -1. Do you agree
d or disagree with Tamera? Explain
1 answer:
I agree only if you have even powers -- even negative ones.
1/i^2 = 1/-1 = - 1
i^0 also gives 1 So far no problem.
It is when you consider the odd numbers that you don't get 1 or -1
You get either -i or i
i^(4n + 1) = i
i^(4n - 1) = -i
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