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FrozenT [24]
3 years ago
7

The graph of was shifted 5 units down and 4 units to the left. What is the equation of the resulting graph?

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

5x+4

Step-by-step explanation:

use the equation mx+b I think this is right but I really dunno

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Express your answer in scientific notation. 4.1 x 10^-2 - 2.6 x 10^-3
bekas [8.4K]

(4.1 \times  {10}^{ - 2}) - (2.6 \times  {10}^{ - 3}) =  \\

(4.1 \times  {10}^{ - 2}) - (0.26 \times  {10}^{ - 2}) =  \\

Factoring \:  \:  {10}^{ - 2}

(4.1 - 0.26) \times  {10}^{ - 2}  =

3.84 \times  {10}^{ - 2}

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
3 years ago
This is timed so pls hurry! i'll mark brainliest
klio [65]

Answer:

x is less than or equal to 272

Step-by-step explanation:

you can spend 272 but you can't go over 272.

8 0
2 years ago
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting
tekilochka [14]

The speed of the satellite is v = √(Gmp/r)

At the geostationary orbit, the gravitational force of attraction of the planet on the satellite equals the centripetal force on the satellite.

Let F = gravitational force  

F = \frac{Gm_{p}m }{r^{2} } where G = universal gravitational constant, mp = mass of the planet, m = mass of satellite and r = radius of geostationary orbit.

Also, the centripetal force F'

F^{'} = \frac{mv^{2}}{r} where m = mass of satellite, v = speed of satellite and r = radius of geostationary orbit.

Since both forces are equal,

F = F'

\frac{Gm_{p}m }{r^{2} } = \frac{mv^{2} }{r}

v^{2} = \frac{Gm_{p} }{r}  \\v = \sqrt{\frac{Gm_{p} }{r} }

So, the speed of the satellite is v = √(Gmp/r)

Learn  more about speed of a satellite here:

brainly.com/question/20162935

5 0
3 years ago
What is the value of x? PLEASE HELP
Natali5045456 [20]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
4) Find the sum of 6\12 and 1\2 .
satela [25.4K]

Answer:

1

Step-by-step explanation:

3 0
3 years ago
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