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siniylev [52]
3 years ago
8

Find the area of the given rhombus​

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

B) Should be your answer of 6cm^2

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Match the correct angle measurement with its letter from the diagram.
igor_vitrenko [27]

Answer:

<C=48 because 90-42=42 as in the other side of the triangle.

<B=42 because vertical angles are always congruent.

<B+<D=90 because <D is 48 because it is vertical to <C

5 0
2 years ago
What ratio is equivalent to 5 to 4
r-ruslan [8.4K]
8:10 16:20 and well yea
7 0
3 years ago
Y= − 2 ( x − 2 ) ( x + 8 ) −2(x−2)(x+8) in standard form
Harlamova29_29 [7]

Answer:

y=-4x^{2} -24x+64

Step-by-step explanation:

y=-2(x-2)(x+8)-2(x-2)(x+8)

y=-2x^{2} +12x+32-2(x-2)(x+8)

y=-2x^{2} -12x+32-2x^{2} -12x+32

y=-4x^{2} -24x+64

7 0
3 years ago
Which equation represents a line which is perpendicular to the line 6x + y = 1?
elena-14-01-66 [18.8K]
Perpendicular: y = -1/6x + 1
3 0
3 years ago
In a certain city, 80 percent of the households have cable television and 60 percent of the households have videocassette record
alexandr1967 [171]

Answer:

60,000

Step-by-step explanation:

Let the total people in the household be 100%

If 80 percent of the households have cable television, 60 percent of the households have videocassette recorders and the number of households that have both cable television and videocassette recorders is 'x' percent. The number of households having ONLY cable television will be 80-x while households having ONLY videocassette will be 60-x.

To get x, we will have;

80-x + 60-x + x = 100

140-x = 100

x = 140-100

x = 40

This shows that 40% of the households have both cable television and videocassette.

If there are 150,000 households in the city, then the number of households that have both cable television and videocassette recorders could be 40% of 150,000

= 40/100 × 150,000

= 60,000

Number of households that owns both television and videocassette could be from 60,000.

3 0
3 years ago
Read 2 more answers
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