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siniylev [52]
3 years ago
8

Find the area of the given rhombus​

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

B) Should be your answer of 6cm^2

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1 1/2 *2 *1 1/2 = 4.5 or 4 1/2

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What is 4534 rounded to rhe nearest hundred
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The house numbers on the North side of Flynn Street are even. In one block, the house numbers begin 1022, 1032, 1042, 1052. What
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The series 1022,1032,1042,1052....

a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term

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What part of 40 is 16?
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Step-by-step explanation:

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A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
3 years ago
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