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luda_lava [24]
4 years ago
10

Which inequality is false?

Mathematics
1 answer:
snow_lady [41]4 years ago
6 0
The false inequality is D 
because -8 is smaller than -1 .
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Complete the equation to represent finding x, the greater integer.<br><br> x(x – ) = 143
mart [117]

Answer:

x would equal -11 or 13

Step-by-step Explanation:

x(x - 2) - 143 = 0

x^2 - 2x - 143 = 0

-2x + x^2 = 143

-143 + (-2x) + x^2 = 0

(x - 13)(x + 11)

x - 13 = 0

Add 13 to both sides

x = 13

x + 11 = 0

Subtract 11 from both sides

x = -11

3 0
3 years ago
an automobile has 20 inch diameter wheels if the wheels revolved three times after the brakes were applied, the stopping distanc
Marrrta [24]

Answer:

188.49

Step-by-step explanation:

use the diameter to find the circumference..

C = d pi          or C = 2r pi

when you plug in 20, you get 62.83

now take that, and multiply it by 3, because the wheels went around three times.

62.83 * 3 = 188.49  inches

i hope this was helpful to you!

stay safe!!

:)

4 0
3 years ago
a wholesaler allows a discount of 25kobo for every 25 naira goods purchased . find the percentage discount allowed.
ZanzabumX [31]

The percentage discount allowed by the wholesaler is 1%

<h3>Percentage</h3>

  • 1 naira = 100 Kobo

25 naira = 25 × 100

= 2500 Kobo

Percentage discount allowed = 25 / 2500 × 100

= 0.01 × 100

= 1%

Therefore, the percentage discount allowed is 1%

Learn more about percentage:

brainly.com/question/843074

#SPJ1

5 0
2 years ago
29+10j= -11<br> Find the value for j
Nezavi [6.7K]
<span>29+10j= -11
</span><span>29+10j - 29 = -11 - 29 (subtract 29 to both sides)
10j = -40
10j/10 = -40/10 (divide both sides by 10)
j = -4


</span>
7 0
3 years ago
Read 2 more answers
4&gt; Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
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