Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
To do this, multiply 3/4 by 1/2 and you end up with 3/8 lb. or 0.375 lb.
Step-by-step explanation:
solution:- from LHS 1-cos²x/sinx
∵ 1-cos²x = sin²x
∴ sin²x /sinx = sinx
from RHS tanx × cosx
∵tanx = sinx×cosx
∴ sinx/ cosx × cosx = sinx
Since, LHS = RHS proved ___
Answer:
60
Step-by-step explanation:
We can easily solve this by finding out how many 60 seconds are in 10 minutes, and then dividing by 10.
To do that, multiply 60 seconds by 10, since there are 60 seconds in each minute.
60*10=600. There are 600 seconds in ten minutes.
Now, divide by 10.
600/10=60
There are 60 intervals of 10 seconds in 10 minutes.
Hope this helps!
Answer:
66%
Step-by-step explanation:
- First, add 20 + 10 = 30. This will give you the total amount of games.
- Now, make this into a fraction for won games. This should be 20/30.
- Next, take 20/30 and simplify it. You should get 2/3 as a fraction.
- Now, take 2 and divide by 3. (2/3) You should get .66 repeating. This is equal to 66%.
- Therefore 66% is the answer.
- Hope this helps! If you need a further explanation please let me know.
