Answer:
Power generated = 4.315 kW
Step-by-step explanation:
Given,
- speed of wind when enters into the turbine, V = 12 m/s
- speed of wind when exits from the turbine, U = 9 m/s
- mass flow rate of the wind, m = 137 kg/s
According to the law of conservation of energy
Energy generated = change in kinetic energy
Since, the air is exiting at same elevation. So, we will consider only kinetic energy.
Energy generated in one second will be given by,


=4315.5 J
= 4.315 kJ
So, energy is generated in one second = 4.315 kJ
Power generated can be given by,

And the energy is generated is already in per second so power generated will be 4.315 kW.
Answer:
yes Dang that baby a thicc boy or girl
Step-by-step explanation:
lol
Answer:
try adding togther
Step-by-step explanation:
Recall that like terms are terms that have the same variable with the same exponent, and that all constants are like terms.
To solve the given equation for y, first, we add like terms:

Now, adding 1.6 to both sides of the equation, we get:

Answer:

Looking at this problem in the book, I'm guessing that you've been
introduced to a little bit of trigonometry. Or at least you've seen the
definitions of the trig functions of angles.
Do you remember the definition of either the sine or the cosine of an angle ?
In a right triangle, the sine of an acute angle is (opposite side) / (hypotenuse),
and the cosine of an acute angle is (adjacent side) / (hypotenuse).
Maybe you could use one of these to solve this problem, but first you'd need to
make sure that this is a right triangle.
Let's see . . . all three angles in any triangle always add up to 180 degrees.
We know two of the angles in this triangle ... 39 and 51 degrees.
How many degrees are left over for the third angle ?
180 - (39 + 51) = 180 - (90) = 90 degrees for the third angle.
It's a right triangle ! yay ! We can use sine or cosine if we want to.
Let's use the 51° angle.
The cosine of any angle is (adjacent side) / (hypotenuse) .
'BC' is the side adjacent to the 51° angle in the picture,
and the hypotenuse is 27 .
cosine(51°) = (side BC) / 27
Multiply each side of that equation by 27 :
Side-BC = (27) times cosine(51°)
Look up the cosine of 51° in a book or on your calculator.
Cosine(51°) = 0.62932 (rounded)
<u>Side BC</u> = (27) x (0.62932) = <u>16.992</u> (rounded)
============================================
You could just as easily have used the sine of 39° .
That would be (opposite side) / (hypotenuse) ... also (side-BC) / 27 .