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Margaret [11]
3 years ago
13

How are physical and chemical changes similar?

Chemistry
2 answers:
kherson [118]3 years ago
7 0

the answer is A                 lqmndcboerhbfiewrhbc                                

Ivan3 years ago
4 0
I believe A. Neither can change the number of atoms of each element that are present
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Given the balanced equation representing a reaction:
GrogVix [38]
 As  aluminium   loses 12 moles  of electrons  oxygen   gain  12 moles of electrons.

Explanation
  4Al +  3 O2→ Al2O3
  first write the ions of  Aluminium  and  oxygen

that is, Aluminium  ion is = Al^3+
              oxygen   ion  is =  O^2-
therefore  one  atom  of Al   loses   3  electrons  moles  while
                one atom of  O gain  2  electrons  moles
                
from equation above there  a total of number of Al atom are 4 =( 1 x4=4)  atoms   while
                                                Oxygen atoms  are  6= ( 3 x2=6) atoms
 
therefore the total  number of Moles of Al lost is = 3  x 4 = 12 moles of                       electrons
     

  total  number of moles of O gained  =  2 x6 = 12 moles  of electrons















6 0
3 years ago
Read 2 more answers
A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu²⁺ salt, and the other half-cell with a Cd bar in the same volume o
Verizon [17]

The E^o_{cell} of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

<h3>What is a voltaic cell?</h3>

A voltaic cell often called a galvanic cell, is an electrochemical device that produces electricity through spontaneous redox processes.

It is divided into two distinct half-cells. A half-cell is made up of an electrode (a metal strip, M) dissolved in a solution containing Mn⁺ ions. M can be any metal.

A wire from one electrode to the other connects the two half-cells. Additionally, a salt bridge links the two half-cells.

To solve the question, we need to write the equations of two half-cells

At the anode, oxidation occurs

Cd(s) \rightarrow Cd^{2+}(aq) + 2e^-

E° = -0.403 V

At the cathode, reduction occurs

Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)

E° = 0.34 V

Overall reaction:

Cd(s) + Cu^{2+}(aq) \rightarrow Cd^{2+}(aq) + Cu(s)

We know

E^o_{cell} = E^o_{cathode} - E^o_{anode}

= 0.34 -(-0.403) = 0.743 V

Also,

ΔG° = -nFE^o_{cell}

Where, n = no of electrons gained or lost

F = Faraday constant

E^o_{cell} = standard potential

ΔG° = -2×96485×0.743 = -143376.71 J = -143.377 kJ

Also,

ΔG° = -RTlnK

-143.377 = -8.314 × 10-3 × 298 × lnK

lnK = 57.87

K = 1.35 × 10²⁵

Hence, The E^o_{cell} of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

Learn more about Voltaic cell:

brainly.com/question/4430225

#SPJ4

6 0
1 year ago
What is the Kelvin temperature for 30°C?
Annette [7]
303.15 would be your answer 
4 0
4 years ago
The Hp scale is a measurement system that indicates the concentration of in solution?
Julli [10]
The pH scale is a measurement system that indicates the concentration of H+ ions in a particular solution.
7 0
3 years ago
Can someone please help me
Vanyuwa [196]

Answer:

1.7

Explanation:

Density = M/V

When you divide 4.52 by 2.6, you get 1.738461538, which can be simplified to 1.7.

7 0
3 years ago
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