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Vaselesa [24]
3 years ago
14

In atomic absorption spectrophophometry, the term "nebulization" implies: (a) The breaking down of fine mist of liquid droplets

into smaller particles (b) Creation of fine suspension of liquid (or solid) particles in a gas (C) The use of hotter flames to atomize high-boiling, refractory elements (d) All of the above
Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:

C

Explanation:

Nebulization is the process by which a mist of a substance is introduced into a flame so that the free atoms are formed. The free atoms are now introduced into the light path for Atomic Absorption spectrophotometry.

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Fe is the limiting reagent

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If an atom has 16 protons, 14 neutrons, and 17 electrons, what is the atom's electrical charge?
daser333 [38]

Answer:

Negative

Explanation:

Neutrons are neutral

Electrons are negative

Protons are positive

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3 0
3 years ago
Which of the following molecules would form a micelle?a. NaClb.CH3COOHc. CH3COO^-NH^4+d. CH3(CH2)^10COO^-Na^+e. CH3(CH2)^10CH3
Goshia [24]

Answer:

CH₃(CH₂)₁₀COONa

Explanation:

The compounds given are

NaCl

CH₃COOH

CH₃COONH₄

CH₃(CH₂)₁₀COONa

CH₃(CH₂)₁₀CH₃

CH₃(CH₂)₁₀COONa will form micelle . Micelle are formed by soap solution which helps in the removal of oily dirt from our clothes . They are spherical shaped tiny droplet of oil which contains the tail of long chain organic compound like salt of long chain fatty  acids . The surface of the droplet is lined with the tip of the chain which consists of negative charge of the tail end . On the average , each micelle contains a specific amount of charge . Due to it , they make colloidal solution in the water and gets washed off my water . The oily dirt is thus removed .

CH₃(CH₂)₁₀COONa   ⇄     CH₃(CH₂)₁₀COO⁻   +    Na⁺

CH₃(CH₂)₁₀COO⁻  part which is long chain of fatty acid gets adsorbed by oily droplet formed by oily dirt  and forming micelle .

7 0
3 years ago
Calculate the mass of water produced when 25.0g of oxygen gas react with
Arlecino [84]

Reaction.-

2H2 + O2 ---> 2H2O

Given,

Mass of Oxygen - 25.0 g

Mass of Hydrogen - 42.0 g

now we have to calculate moles

moles of O2 = 25/16 = 1.5625 moles

Moles of H2 = 42/2 = 21 moles

Hydrogen gas is in excess,

now using reaction

1 mole of oxygen gas forms 2 moles of H2O

1.5625 mole of Oxygen gas will form x mole of H20

x = 3.125 moles

molar mass of H2O is 18g

mass of 3.125moles of water = 3.125 × 18 = 56.25 g.

Hence the mass of water produced when 25.0g of oxygen gas react with 42.0g of hydrogen gas is 56.25 grams

4 0
3 years ago
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