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ivolga24 [154]
3 years ago
5

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10

5 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 31 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; in other words, rate is the amount that diffuses over the time it takes to diffuse.)

Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Answer: the molar Mass of the unknown gas is 367.12

Explanation:Please see attachment for explanation

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What mass of NaCl is dissolved in 150 g of water in a .050<br> msolution?
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Answer:

0.4383 g

Explanation:

Molality is defined as the moles of the solute present in 1 kg of the solvent.

It is represented by 'm'.

Thus,  

Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}

Given that:

Mass of solvent, water = 150 g = 0.15 kg ( 1 g = 0.001 g )

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So,

0.050=\frac {Moles\ of\ the\ solute}{0.15}

Moles = 0.050\times 0.15\ mol= 0.0075\ mol

Molar mass of NaCl = 58.44 g/mol

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<h2>Answer:</h2>

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