Answer:
The number of OH group found in found in a 6 carbon alditol is 6
Explanation:
The structure of a 6 carbon alditol is shown on the first uploaded image
A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10
5 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 31 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; in other words, rate is the amount that diffuses over the time it takes to diffuse.)
1 answer:
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Answer:
Volume of stock solution needed = 6.0299 mL
Explanation:
<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.
This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.
<u>Data:</u>
M1 = 6.01 M stock solution concentration
M2 = 0.3624 M diluted solution concentration
V2 =100 mL diluted solution volume
V1 = ? stock solution volume
M1 * V1 = M2 * V2