A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10
5 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 31 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; in other words, rate is the amount that diffuses over the time it takes to diffuse.)
To find out the number of water molecules produced simply use Avogadro’s constant, where 1 mol of any compound is equal to 6.02 x 10^23 molecules of the substance.