Answer: 0.45 J / g °C
Explanation: solution attached.
Heat is equal to the product of mass, specific heat and change in temperature.
Q= mc∆T
Derive the equation to find c
c = Q / m∆T substitute the values
c = 21.6 J / 2.0g ( 24°C - 5°C)
c = 0.45 J / g ° C
The two solutions that have similar solubilities at 40°C will be Na₂HAsO₄ and Na₂SO₄.
<h3>What is solubity ?</h3>
It is the ability of a solute to be dissolved, especially in water.
As the temperature increases the solubility of the gas generally decreases"
According to given information and graph attached as reference ;
Lear more about solubility here ;
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Answer: 0.67 ml
Explanation:
According to the dilution law,
where,
= concentration of stock solution = 226 mg/ml
= volume of stock solution = ?
= concentration of working solution= 15 mg/ml
= volume of working solution= 10 ml
Putting in the values we get:
Thus volume of stock solution needed to dilute to have 10mL of working solution at the above concentration is 0.67 ml