we find the number of moles with the formula
pV=nRT
27C=300k
3.2*30=n*0.082*300
n=96/24.6=3.9 moles
we have the mass ant the number of moles so we can calculate the molar mass
283.3/3.9=72.64g/moles
that means X's mass is 72.64/2=36.3 so the element is Kr(Kriptonium)
Given:
Diprotic weak acid H2A:
Ka1 = 3.2 x 10^-6
Ka2 = 6.1 x 10^-9.
Concentration = 0.0650 m
Balanced chemical equation:
H2A ===> 2H+ + A2-
0.0650 0 0
-x 2x x
------------------------------
0.065 - x 2x x
ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)
solve for x and determine the concentration at equilibrium.
C,
takes dead things, makes them into other things
The <span>covalent bonds are predicted for each atom are :
</span>(a)F = 1
(b) Si = 4
(c) Br = 1
(d) O = 2
(e) P = 3
(f) S = 2
