Answer: 1.14mol
Nitrogen molar mass=14g/mol
N2 molar mass=14*2=28g/mol
31.9g(1/28)=1.14mol N2
Explanation:

According to mass action,
![\textrm{rate}=-\dfrac{\Delta[\textrm A]}{2\Delta t}=k[\textrm A]^2](https://tex.z-dn.net/?f=%5Ctextrm%7Brate%7D%3D-%5Cdfrac%7B%5CDelta%5B%5Ctextrm%20A%5D%7D%7B2%5CDelta%20t%7D%3Dk%5B%5Ctextrm%20A%5D%5E2)
Where, k is the rate constant
So,
![\dfrac{d[A]}{dt}=-k[A]^2](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5BA%5D%7D%7Bdt%7D%3D-k%5BA%5D%5E2)
Integrating and applying limits,
![\int_{[A_t]}^{[A_0]}\frac{d[A]}{[A]^2}=-\int_{0}^{t}kdt](https://tex.z-dn.net/?f=%5Cint_%7B%5BA_t%5D%7D%5E%7B%5BA_0%5D%7D%5Cfrac%7Bd%5BA%5D%7D%7B%5BA%5D%5E2%7D%3D-%5Cint_%7B0%7D%5E%7Bt%7Dkdt)
we get:
![\dfrac{1}{[A]} = \dfrac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20%5Cdfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where,
is the concentration at time t
is the initial concentration
Half life is the time when the concentration reduced to half.
So, ![[A_t]=\frac{1}{2}\times [A_0]](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5BA_0%5D)
Applying in the equation as:
![t_{1/2}=\dfrac{1}{k[A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cdfrac%7B1%7D%7Bk%5BA_o%5D%7D)
Animal cells have a centrosome and lysosomes, whereas plant cells do not.
Answer:
mass = 963.53 grams
Explanation:
mass = moles x molar mass
m = 9.45 x 101.96 (molar mass of Al2O3)
m = 963.53g
Th equilibrium shifts to the left