Answer:
13u
Step-by-step explanation:
These are like terms so you may combine them
4u+9u=13u
Answer:
The answer is below
Step-by-step explanation:
The distance traveled the first day = Distance from San Jose to Santa Barbara = 320 mile.
The distance traveled the second day = Distance from Santa Barbara to Los Angeles.
But From San Jose to Los Angeles = 425 mile. Therefore:
Distance From San Jose to Los Angeles = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles
425 = 320 + Distance from Santa Barbara to Los Angeles.
Distance from Santa Barbara to Los Angeles = 425 - 320 = 105 mile
The distance traveled the second day = Distance from Santa Barbara to Los Angeles = 105 miles
The distance traveled the first day + The distance traveled the second day = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles = 320 + 105 = 425 miles
The distance traveled the first day + The distance traveled the second day = 425 miles
The answer is: t = 1
You need to separate t from everything to figure out what it is.
Step 1: Subtract 9 from both sides, so we get 7 - 2t = 5t
Step 2: Add 2t to both sides, so we get 7 = 7t.
Step 3: Divide by 7, meaning t = 1.
Next you should check your work. If we plug 1 in for t, we get 14 = 14, so the answer is correct.
Hope this helps!
Answer:
area of BMDN 8 ft²
Step-by-step explanation:
In BMDN the diagonals are BD and MN.
MN is 12/3 = 4 ft long, and BD = 4 ft.
A rhombus with equal diagonals is a square, so BMDN is a square.
In the right triangle BDN, the diagonal BD is the hypotenuse, then:
DN² + NB² = BD²
but DN = NB, then:
2*DN² = 16 ft²
DN² = 8 ft²
The area of BMDN is computed as one of its sides squared. Then, DN² is its area
