Answer:
The algebraic expression is (P-0.15p) = 0.85p
Step-by-step explanation:
Here, we want to write an algebraic expression to model the situation at hand;
Original price p of an item less a 15% discount
What this mean is that we want to remove a 15% discount from the original price P
That term ‘less’ means we are subtracting
so 15% of p would be;
15/100 * p = 15p/100 = 0.15p
So 15% of P less P is (P-0.15P) = 0.85P
B. 17.16 represents a credit of $17.16; "credits" mean that you're receiving something, so it's added. A is incorrect because it shows the money being taken away and that isn't what a credit does. C and D aren't even the same amount of money in the question, so they aren't your answer either.
<h2>
Step-by-step explanation:</h2>
Interest, is an additional money paid for borrowing money. it could be simple or compound interest.
simple interest= p×T×R/100
when interest is compounded annually
F= p(1+r)^t
F= future value
p= principal
r= rate
t= time
compound interest is calculated based on the initial and accumulated interest.
<h2>interest Linda earns</h2><h3>fist year</h3>
F= p(n+r)^n
F= 10000(1+0.02)^1
F= 10000×1.02= $10200
interest= 10200-10000
interest = $200
second year
F = 10200(1+0.02)^1
F=10200×1.02= $10404
Interest= 10404-10200
interest= $204
third year
F= 10404(1+0.02)^1
F= 10404(1.02)
F = $10612.08
interest= 10612.08-10404
interest= $208.08
<h2>Bob's interest</h2><h2>I= p×t×R/100</h2>
first year
I=10000×1×0.02/100
interest= $2
second year
I= 10000×2×0.02/100
interest= $4
for the third year
I =10000×3 × 0.02/100
interest= $6
<h2>check answer above for final computation</h2>
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