Find the 6th term of a geometric sequence with t1=5 and r = -1/2

1 answer:

5 0

In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,

An = (A₀)(r)ⁿ ⁻ ¹
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms.

Substitute the known values to the equation,

An = (5)(-1/2)⁶ ⁻ ¹
An = -5/32

Hence, the answer to this item is the third choice, -5/32.

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1.Change 65% into a decimal. Move the decimal two places to the left and you get 0.65.

2. Multiply 0.65 by 50.
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3. Since you are decreasing 140 by 65%, subtract 140 by 91.
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