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gogolik [260]
3 years ago
8

How exactly do i do this?

Mathematics
1 answer:
pentagon [3]3 years ago
8 0
The perimeter of a square is 4s where s is the side length. Since the side length is sqrt 5, the perimeter is 4sqrt5 cm.
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Simplify 4(x-y)-8(-7x+6y)
aliya0001 [1]
The answer is 60x-52y

Hope that helped!
8 0
3 years ago
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Which of the following linear systems has a solution <br> (5,0)<br> SOMEONE PLS HELPPP
Korvikt [17]

Answer:

D

Step-by-step explanation:

out of the choices

A) 2x-y=-2

3x+2y=-10

B) x+4y=3

2x+5y=3

C) 2x+3y=5

x-4y=-14

D) 3x+4y=15

x+y=5

only the system in D has a solution of x=5 and y=0

solve by substitution x+y=5 so x=5-y

plug into the other equation so 3(5-y)+4y=15

distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms

so y=0 then put that value back into the other equation

so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)

Hope this helps! :)

3 0
3 years ago
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CosA×cos2A+sinA×sin2A=cos (2A-A)​
Aleksandr-060686 [28]

Answer:

csc

A

, as desired!

Step-by-step explanation:

cos

2

A

sin

A

+

sin

2

A

cos

A

,

=

cos

2

A

cos

A

+

sin

2

A

sin

A

sin

A

cos

A

,

=

cos

(

2

A

−

A

)

sin

A

cos

A

,

=

cos

A

sin

A

cos

A

,

=

1

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csc

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, as desired!

7 0
3 years ago
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
3 years ago
Find the value of x in the figure
MA_775_DIABLO [31]

Answer:

x = 100

Step-by-step explanation:

57 \degree + (x + 23) \degree = 180 \degree..(straight \: line \:  \angle s) \\ (x + 80) \degree = 180 \degree \\ x + 80 = 180 \\ x = 180 - 80 \\  \huge \red{ \boxed{x = 100}}

6 0
4 years ago
Read 2 more answers
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