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Dennis_Churaev [7]
3 years ago
5

Please awnser this i need it for my quiz

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Answer:

The last one.

Step-by-step explanation:

hope this helps :)

tamaranim1 [39]3 years ago
5 0
Its the last answer -6m-n+3
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Step-by-step explanation:

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In a recent study of statistics students, a random sample of students were asked to provide the number of hours per week they sp
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Answer:

ME=\frac{Upper-Lower}{2}= \frac{8.15-6.55}{2}= 0.80

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

For this case the confidence interval is given by (6.55,8.15). And we can estimate the margin of error with this formula since the confidence interval is symmetrical:

ME=\frac{Upper-Lower}{2}= \frac{8.15-6.55}{2}= 0.80

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If m ∠ 1 = 101, what is the value of X?
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if a distribution of raw scores were plotted and then the scores were transformed to z scores, would the shape of the distributi
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