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zhenek [66]
3 years ago
5

A spinner that has 4 equal parts that are the colors blue, green, red, and yellow. The spinner is spun 12 times. It lands on blu

e 1 time.
Part A) What is the experimental probability of the spinner landing on blue?

Part B) Compare the experimental and theoretical probabilities of the spinner landing on blue. If the probabilities are not close, explain a possible reason for the discrepancy.
Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

The experimental probability would be 1/12 and the theoretical probability would be 1/4. The probabilities were not close so a possible reason for the discrepancy would be the blue color on the spinner was slippery.

Step-by-step explanation:

So to start out you need to find out the experimental probability. If the spinner landed on blue 1 time out of 12 different times, you write that as a fraction of 1/12. So 1/12 is the experimental probability. It also asks for the theoretical probability. There are 4 parts of the spinner so 4 is the denominator, one of those possibilities is the one we want so 1 is the numerator, so the theoretical is 1/4. The probabilities were not close so a possible reason for the discrepancy would be the blue color on the spinner was slippery.

Just to tell you what theoretical and experimental probabilities mean is that the theoretical is the possible outcome before you do it. Experimental is where you judge your probability off of past events.

wel3 years ago
4 0
The expiremental probability would be 1/4 and the theoretical would be the same thing ecept you multiply by the number of times
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Answer:

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Step-by-step explanation:

1) The given information are;

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Type of interest rate = Compound interest

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Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

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Where;

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Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

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The year in which the amount of money in Laurie's account will become double = year 2032.

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