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vlabodo [156]
2 years ago
9

Solve for y. 2/3 + y - 4/5 = 1/3 Enter your answer in the box. y =

Mathematics
2 answers:
lys-0071 [83]2 years ago
4 0
Step 1. Simplify \frac{2}{3} +y- \frac{4}{5} to y- \frac{2}{15}

y- \frac{2}{15} = \frac{1}{3}

Step 2. add \frac{2}{15} to both sides

y= \frac{1}{3} + \frac{2}{15} 

Step 3. Simplify \frac{1}{3} + \frac{2}{15} to \frac{7}{15}

y= \frac{7}{15}

Done! :) (Decimal Form: 0.4667)
erica [24]2 years ago
3 0
<span>2/3 + y - 4/5 = 1/3
         y = 1/3 - 2/3 + 4/5
         y = -1/3 + 4/5
         y =-5/15 + 12/15
         y = 7/15</span>
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What requirements must be​ satisfied? select all that apply.
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1/(x-2)+1/(x+3)=1/5 solve the problem for me​
Gennadij [26K]

════════ ∘◦❁◦∘ ════════

<h3>Final value : x² -9x - 11</h3>

════════════════════

<h3>Step by step </h3>

\frac{1}{(x - 2)}  +  \frac{1}{(x + 3)}  =   \frac{1}{5}

\frac{(x + 3) + (x - 2)}{(x - 2)(x + 3)}  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2} + 3x - 2x - 6 }  =  \frac{1}{5}

\frac{2x + 1}{ {x}^{2}  + x - 6}  =  \frac{1}{5}

2x + 1 = ⅕ × (x² + x - 6)

2x + 1 = ⅕x² + ⅕x - 6/5

1/5x² +1/5x - 2x - 6/5 - 1 = 0

1/5x² -9/5x - 11/5 = 0

x² - 9x - 11 = 0. #times by 5

════════════════════

#Give me brainliest pls im tired typing all of this

8 0
3 years ago
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wariber [46]
1 and 1/2 is the right one
8 0
2 years ago
Read 2 more answers
Given the graph of a function f. Identify the function by name. Then Graph, state domain &amp; range in set notation:A) f(x) +2B
WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

\mleft\lbrace x\in\R\mright\rbrace

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

\mleft\lbrace y\in\R\mright|y\ge0\}

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0
11 months ago
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