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3 years ago

I need help to find the rule.

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

U multiply every thing by 5

Sonbull [250]3 years ago

3 0

Lololololol. I long since forgot how to do this. rip

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Write as an equation: Alice, Barbara, and Carol are sisters. Alice is 3 years younger than Barbara, and Barbara is 5 years young

Dmitrij [34]

a+b+c=68

b-3=a

c-5=b

now just solve the system of equations, substitue so that there are only b's in the equation:

a+b+c=68

(b-3) + b + (b+5) = 68

3b=66

b=22

Therefore Barbara is 22

4 0

3 years ago

Please write it down step by step :)

grandymaker [24]

Answer:

-6

Step-by-step explanation:

Some nasty order of operations coming up.

Firstly, deal with that squared:

-12 / 3 * (-8 + 16 - 6) + 2

Simplify the bracket:

-12 / 3 * 2 + 2

Simplify -12 / 3:

-4 * 2 + 2

Simplify -4 * 2:

-8 + 2

Simplify:

-6

3 0

3 years ago

Help me find m PLEASE THANK YOUUUU

julia-pushkina [17]

Answer:

the m angle ABC is 19x+12

3 0

2 years ago

Read 2 more answers

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

5 0

4 years ago

Samuel deposits $1,800 in an account that earns 12% simple annual interest. How many months will it take for Samuel's account ba

Artemon [7]

In order to use the simple interest formula, we first define the variables. The interest would be equal to Samuel's desired amount $ 2,488 minus the principal amount of $ 1,800 which is then equal to $ 688. The rate must be in decimal form which is equal to 0.12 while t is expressed in years. Substituting the values, t is equal to 3. Thus, it will take 36 <span>months for Samuel's account balance to reach $2,448. </span>

6 0

3 years ago