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Snezhnost [94]
3 years ago
6

Rewrite without absolute value for the given condition : y=|x−5|+|x+5|, if −5 I WILL AWARD BRAINLIEST!!! PLEASE HELP!!!!!

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0

y = | x -5| + |x+5|

as range of x is

-5 < x < 5

we can see if we put x = 0 we get

y = 10

we put any value of x in given range first term is always negative without absolute. and 2nd term is always positive

so

y = | x -5| + |x+5|

= -( x-5) + x + 5

= - x + 5 + x + 5

= 10

so

y = 10 where -5 < x < 5

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Observe the figure below.

    Statement                                                                          Reason

1. AC and BD bisect each other                                             Given

2. AE = EC and BE = ED                                                         Definition of bisection

3. m \angle AEB = m \angle CED                       Vertical angle theorem

Vertical angle theorem states " When two lines intersect each other, the vertically opposite angles are always equal".

4. \Delta ABE \cong \Delta CDE                         SAS criterion for congruence

5. m \angle ACD = m \angle CAB           Corresponding angles of congruent triangles are congruent

6. AB \parallel CD                                 Converse of alternate interior angle theorem

7.  m \angle BEC = m \angle AED                   Vertical angle theorem

8.  \Delta BEC \cong \Delta DEA            SAS criterion for congruence

9.  BC \parallel AD                                 Converse of alternate interior angle theorem

As, \Delta BEC \cong \Delta DEA, so m \angle CBD = m \angle BDA as corresponding parts of corresponding triangles are equal. As these angles are alternate interior angles, so the lines BC and AD are parallel by  "Converse of alternate interior angle theorem".

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Answer:

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Step-by-step explanation:

An element p of the set H has the form

p(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}

where a_{0},a_{1},a_{2},a_{3},a_{4} are rational coefficients.

The operations of addition and scalar multiplication are defined as follows:

p(x)+q(x)=(a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+x_{4}x^4)+(b_{0}+b_{1}x+b_{2}x^{2}+b_{3}x^{3}+b_{4}x^{4})=(a_{0}+b_{0})+(a_{1}+b_{1})x+(a_{2}+b_{2})x^{2}+(a_{3}+b_{3})x^{3}+(a_{4}+b_{4})x^{4}

\lambda p(x)=\lambda (a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4})=\lambda a_{0}+\lambda a_{1}x+\lambda a_{2}x^{2}+\lambda a_{3}x^{3}+\lambda a_{4}x^{4}

The properties that H, together the operations of vector addition and scalar multiplication,  must satisfy are:

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  6. Distributive properties.

This is not difficult with the definitions given. The most important part is to show that H has a additive identity, which is the zero polynomial, that is closed under vector addition and scalar multiplication. This last properties comes from the fact that \mathbb{Q} is a field, then it is closed under sum and multiplication.

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