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erica [24]
2 years ago
8

Answer the following questions.

Mathematics
1 answer:
schepotkina [342]2 years ago
7 0
<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind  \: of\:junk} & \bf{Price  \: of \:  1  \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \:  Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: newspaper = Rs.5}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  20  \: kg  \: newspaper = Rs.20 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  20  \: kg  \: newspaper = Rs.100}}}

\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost  \: of \:  20  \: kg  \: newspaper = Rs.100}}}}}}

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

\rule{200}{1.5}

2. What is the cost of 5 kg Iron?

\quad{\longrightarrow{\sf{Cost\: of \:  1  \: kg  \: iron = Rs.10}}}

\quad{\longrightarrow{\sf{Cost\: of \:  5  \: kg  \: iron = Rs.10 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  5  \: kg  \: iron = Rs.50}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: iron = Rs.50}}}}}

<u>∴ The cost of 5 kg iron is Rs.50.</u>

\rule{200}{1.5}

3. What is the cost of 9 kg Plastic?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: plastic = Rs.8}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.8 \times 9}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.72}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \:  9  \: kg  \: plastic = Rs.72}}}}}

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

\rule{200}{1.5}

4. What is the cost of 7 kg Brass?

\quad{\longrightarrow{\sf{Cost  \: of \:  1  \: kg  \: brass = Rs.50}}}

\quad{\longrightarrow{\sf{Cost\: of \:  7  \: kg  \: brass = Rs.50 \times 7}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  7  \: kg  \: brass = Rs.350}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: brass = Rs.350}}}}}

<u>∴ The cost of 7kg brass is Rs.350.</u>

\underline{\rule{200pt}{2pt}}

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(1/4)x+1=32 <br><br> -A: -7/2<br> -B: 2<br> -C: -2<br> -D: 3/2
777dan777 [17]
The answer is b due to pemdas
4 0
3 years ago
James has $5.00 more than three times what Catherine has. Together they have $41.00. How much does each student have?
Tpy6a [65]
Hey.

acc'g to the conditions :

Let Catherine has x
and James has 5 + 3x

Then,

5 + 4x = 41 \\ \\ \implies 4x +5 -5 = 41-5 \\ \\ \implies 4x = 36 \\ \\ \implies x= \dfrac{36}{4} \\ \\ \implies x = 9

Hence

• Catherine has = x = $9,
• and James has = 5 +3x = 5 + 3(9) = $32

Thanks.
7 0
3 years ago
I just want to make sure this is accurate!! Thanks
egoroff_w [7]

Answer:

Looks good to me!

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
Two cars leave towns 360 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou
mixer [17]
Let x = speed of the first car

the second car is 12 km slower so the seconds car speed is x-12

 they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
 
they drove 360 km
 so you have 2x + 2(x-12) = 360
 solve for x

2x+2(x-12) = 360

2x + 2x-24 = 360

4x-24 = 360

4x = 384
x = 384/4
x = 96

1st car drove at 96 km per hour

slower car drove at 96-12 = 84 km per hour



5 0
4 years ago
A woodworker makes wooden checkerboards. her profit is a function of the price she charges. this graph shows her total profits,
pantera1 [17]

Answer:

Option B.

Step-by-step explanation:

Remember that the profit is defined as the difference between the revenue and the cost.

So, having a profit y = 0 means that the woodworker did not win nor lose anything.

Then the zeros of the function, the values of x such that the graph intersects the x-axis, are the prices such that she does not win nor loss anything.

In the graph we can see that the zeros are at:

x = 15 (the first one)

x = 70 (the second one)

so the zeros are at x = 15 and x = 70, and these are the prices such that the profit is zero, so at these prices she does not make nor lose money.

The correct option is B.

8 0
3 years ago
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