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erica [24]
2 years ago
8

Answer the following questions.

Mathematics
1 answer:
schepotkina [342]2 years ago
7 0
<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind  \: of\:junk} & \bf{Price  \: of \:  1  \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \:  Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: newspaper = Rs.5}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  20  \: kg  \: newspaper = Rs.20 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  20  \: kg  \: newspaper = Rs.100}}}

\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost  \: of \:  20  \: kg  \: newspaper = Rs.100}}}}}}

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

\rule{200}{1.5}

2. What is the cost of 5 kg Iron?

\quad{\longrightarrow{\sf{Cost\: of \:  1  \: kg  \: iron = Rs.10}}}

\quad{\longrightarrow{\sf{Cost\: of \:  5  \: kg  \: iron = Rs.10 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  5  \: kg  \: iron = Rs.50}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: iron = Rs.50}}}}}

<u>∴ The cost of 5 kg iron is Rs.50.</u>

\rule{200}{1.5}

3. What is the cost of 9 kg Plastic?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: plastic = Rs.8}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.8 \times 9}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.72}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \:  9  \: kg  \: plastic = Rs.72}}}}}

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

\rule{200}{1.5}

4. What is the cost of 7 kg Brass?

\quad{\longrightarrow{\sf{Cost  \: of \:  1  \: kg  \: brass = Rs.50}}}

\quad{\longrightarrow{\sf{Cost\: of \:  7  \: kg  \: brass = Rs.50 \times 7}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  7  \: kg  \: brass = Rs.350}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: brass = Rs.350}}}}}

<u>∴ The cost of 7kg brass is Rs.350.</u>

\underline{\rule{200pt}{2pt}}

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(x, y) → (x - 3, y + 5 )

Step-by-step explanation:

A shift of 3 units to the left means subtract 3 from the original x- coordinate.

A shift of 5 units up means add 5 to the original y- coordinate.

Thus the rule representing the translation is

(x, y ) → (x - 3, y + 5 )

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If the perimeter of this triangle is to be no more than 77 feet, write an inequality and
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Consider the sides of the triangle are 4x+10, 2x-5 and 18 (in feet).

Perimeter of this triangle is to be no more than 77 feet.

To find:

The inequality and solution of the inequality.

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Perimeter of a triangle is the sum of all side.

Perimeter of given triangle =(4x+10)+(2x-5)+18

Perimeter of this triangle is to be no more than 77 feet. It means perimeter must be less than or equal to 77.

(4x+10)+(2x-5)+18\leq 77

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Divide both sides by 6.

x\leq \dfrac{54}{6}

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A rectangular prism has a base length of 6 units, base
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Answer:

The lateral area rectangular prism is 88 unit^2.

The area of the two bases of rectangular prism together is  60 unit^2.

The total surface area rectangular prism is 148 unit^2.

Step-by-step explanation:

Height of the rectangular prism = h = 4 units

Length of the base of the rectangular prism = l = 6 units

Width of the base of rectangular prism = b = 5 units

Rectangular prism = Cuboid

Lateral surface area of cuboid = L.S.A = 2 × h × (l+b)

Lateral surface area of rectangular prism :

L.S.A=2\times 4 units(6 units+5units)=88 units^2

Area of the base = l × b

Area of the base of the rectangular prism = 6 unit\times 5 unit=30 unit^2

Area of the two bases  = 2\times 30 unit^2=60 unit^2

Total surface area of cuboid = T.S.A = 2 ×(lb+bh+hl)

Lateral surface area of rectangular prism :

T.S.A=2\times (6unit\times 5unit+5 unit\times 4unit+4 unit\times 6 unit)

=148 unit^2

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