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noname [10]
3 years ago
10

What is the common difference of the arithmetic sequence 1/5, 6/5 , 11/5 ,16/5 , ...?

Mathematics
2 answers:
stepladder [879]3 years ago
8 0
+ 5/5 each time

hope this helps
snow_lady [41]3 years ago
8 0
The common difference is 1 because if you simplify the improper fractions, each hole number is 1 greater than the one before. So the common difference is 1 or 5/5
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How to Graph 3(x-2)2+6
BARSIC [14]

Answer:

n/a

Step-by-step explanation:

it just needs more work on the vertex.

3 0
3 years ago
3.) 2x + 4 = -3x - 2; x = 1<br><br>Determine if the value of x is a solution to the equation​
guajiro [1.7K]

Answer:

x = 1 is not a solution to the equation

Step-by-step explanation:

2x + 4 = -3x - 2            x = 1

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2 + 4 = -3 - 2

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3 years ago
A line parallel to a line that has a slope of 0 would have the slope of? geometry/algebra
garri49 [273]

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Step-by-step explanation:

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8 0
3 years ago
Marlene is solving a number puzzle involving three rational numbers a, b, and c. Here are her clues:
rusak2 [61]
A/c = 8.....a = 8c
a * c = 2 ...a = 2/c
a/b = -16 ...a = -16b
a * b = -1....
b/c = -0.5

2/c = 8c
2 = 8c^2
1/4 = c^2
sqrt 1/4 = c
0.5 (or 1/2) = c <===

a * c = 2
0.5a = 2
a = 2/0.5
a = 4 <===

a = -16b
4 = -16b
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5 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

Sa= 1.64

t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017

(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

6 0
3 years ago
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