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Ganezh [65]
4 years ago
8

Which equivalence factor should you use to convert from 38.2 grams of K to moles of K?

Chemistry
2 answers:
UNO [17]4 years ago
6 0

<span>In order convert the mass of a substance to its number of moles The conversion factor is the reciprocal of the molecular weight of the substance. Hence, for the given element in the problem- potassium, the equivalence factor is d. </span><span>(1 mol K/39.10 g K). </span>

motikmotik4 years ago
6 0

Answer: (38.2 g K/39.10 g K)

Explanation:

To convert given masses into moles we use the formula :

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}

Given:

Mass of K= 38.2 grams

Molar mass of K=  39.10 g/mol

Putting in the values in the given formula, we get:

Moles of K= \frac{38.2g}{39.10g/mole}=0.98moles

Thus the moles are 0.98 moles.

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A twenty-eight-liter volume of gas contains 11 g methane, 1.5-gram nitrogen and 16-gram carbon dioxide. Determine partial pressu
GREYUIT [131]

Based on Dalton's Law, for a mixture of gases, the total pressure is the sum of the partial pressure of each gas.

Partial pressure (p) of each gas is related to the total pressure (P) as follows:

p = X * P----------(1)

where X is the mole fraction of that gas

X = moles of a particular gas/total number of moles of all gases in the mixture--------------(2)

Step 1: Calculate the moles of each gas

Mass of methane, CH4 = 11 g

Mass of nitrogen, N2 = 1.4 g

Mass of carbon dioxide, CO2 = 16 g

# moles of CH4 = 11 g/16 gmol-1 = 0.6875

# moles of N2 = 1.4/28 = 0.05

# moles of CO2 = 16/44 = 0.3636

Total moles = 0.6875+0.05+0.3636 = 1.1011

Step2: Calculate mole fractions of each gas

Based on equation (2)

X(CH4) = 0.6875/1.1011 = 0.6244

X(N2) = 0.05/1.1011 = 0.0454

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Based on ideal gas equation:

PV = nRT

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Based on equation:

p(CH4) = 0.6244*0.962 atm = 0.601 atm

P(N2) = 0.0454*0.962 atm = 0.044 atm

P(CO2) = 0.3302*0.962 atm = 0.318 atm


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Answer:

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Explanation:

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