Answer:
Percentage composition = 14.583%
Explanation:
In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.
Percentage composition by mass of Nitrogen
Nitrogen = 14g/mol
In one mole of the compound;
Mass of Nitrogen = 1 mol * 14g/mol = 14g
Mass of compound = 1 mol * 96.0 g/mol = 96
Percentage composition of Nitrogen = (Mass of Nitrogen / Mass of compound) * 100
percentage composition = 14/96 * 100
Percentage composition = 0.14583 * 100
Percentage composition = 14.583%
2CH3COOH +Na2CO3 ----> 2CH3COONa + H20 + CO2
know you can find what all products formed from his reaction
Answer:
V₂ = 648.53 mL
Explanation:
Given data:
Initial volume of gas = 490. mL
Initial temperature = -35°C (-35 + 273 = 238 k)
Final temperature = 42°C = (42+273 = 315 k)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 490 mL × 315 K / 238 k
V₂ = 154350 mL.K / 238 K
V₂ = 648.53 mL
the answer is B because I jus did that
