is the equilibrium constant expression for
NH₂HS(S) → NH₂(g) + H₂S(g). Hence, option A is correct.
<h3>Definition of equilibrium constant.</h3>
A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.
Equilibrium constant for the NH₂HS(S) → NH₂(g) + H₂S(g) will be:
![K_c = \frac{[Product]^{coefficient}}{[Reactantt]^{coefficient}}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BProduct%5D%5E%7Bcoefficient%7D%7D%7B%5BReactantt%5D%5E%7Bcoefficient%7D%7D)
![K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BNH_2%5D%5E%7B1%7D%5BH_2S%5D%5E%7B1%7D%7D%7B%5BNH_2HS%5D%5E%7B1%7D%7D)
Hence, option A is correct.
Learn more about the equilibrium constant here:
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Answer:
This is based on most likely so it's A.Fe
Answer:
24%
Explanation:
From the question, the limiting reactant is H2S.
The reaction equation is;
2H2S + O2 → 2S + 2H2O
Number of moles of H2S reacted = 22g/34 g/mol = 0.647 moles
According to the reaction equation;
2 moles of H2S yields 2 moles of sulphur
0.647 moles of H2S yields 0.647 moles of sulphur
So;
Theoretical yield of sulphur = 0.647 moles * 32 g/mol = 20.7 g
Actual yield = 5 g
% yield = actual yield/theoretical yield * 100
% yield =5 g/20.7 g * 100
% yield = 24%
Answer:
A. 0.143 M
B. 0.0523 M
Explanation:
A.
Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).
KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄
The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:
1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol
The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.
5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:
M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M
B.
Let's consider the neutralization of potassium hydroxide and perchloric acid.
KOH + HClO₄ → KClO₄ + H₂O
When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

Answer:
The answer is B.
Explanation:
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.