Question

Use the following balanced reaction to solve 1-3:

Answer 1

Answer:

1.96g H2

Explanation:

P4 = 123.9g/mol

H2 = 2.02g/mol

$\frac{20g P_{4} }{1}$ * $\frac{1 mol P_{4} }{123.9g}$ * $\frac{6 mol H_{2} }{1 mol P_{4} }$ * $\frac{2.02g H_{2} }{1 mol H_{2} }$ = 1.96g H2