Answer:
semipermeability
Explanation:
partially but not freely or wholly permeable specifically : permeable to some usually small molecules but not to other usually larger particles a semipermeable membrane.
Answer:
bdndbdjdbdjdbdjdbsidbdidbsjsbsisbsidbd
When naming an ionic compound, write the name of the cation, which is the metal first. Then, write the name of the anion, which is the nonmetal. However, you remove the last 2-3 letters and replace suffixes.
1. RbF --> Rubidium Fluoride
Change fluorine to fluoride
2. CuO --> Copper (II) Oxide
Change oxygen to oxide. Oxide has a charge of -2. Since no subscripts are written, it means they have the same opposite charge. So, we use Copper (II).
<span>3. (NH</span>₄<span>)</span>₂<span>C</span>₂<span>O</span>₄ ---> Ammonium Oxalate
NH₄ is ammonia, but we change it to ammonium for polyatomic ions.
Answer:
Options B and C are the two criteria that are most essential
Explanation:
When trying to develop a novel process, <u>it is important that the new process involves the use of equipment that can be operated safely by workers so as to prevent death or injury in the cause of handling this equipment</u>. If this equipment is seen not to be safe or cannot be handled safely by workers, it can/will force workers to previous or alternative methods that require more safe equipment.
Also, the process must be able to maximize the most of the reactants, i.e <u>the process must be able to convert a good percentage of the reactants into the desired product (phosphorus pentachloride) since that is the focus</u>. This will also lead to reduction of byproducts produced which could be useful or otherwise (a loss).
Answer:
Actual yield = 86.5g
Explanation:
Percent yield = 82.38%
Theoretical yield = 105g
Actual yield = x
Equation of reaction,
CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O
Percentage yield = (actual yield / theoretical yield) * 100
82.38% = actual yield / theoretical yield
82.38 / 100 = x / 105
Cross multiply and make x the subject of formula
X = (105 * 82.38) / 100
X = 86.499g
X = 86.5g
Actual yield of CaCl₂ is 86.5g
