Write the equation of a line through the given point with the given slope (0,6);m undefined
1 answer:
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Answer: x = 14/23
Step-by-step explanation:
3x-6=4(2-3x)-8x
3x-6=8-12x-8x --> Expand 4(2-3x)
3x-6=8-20x --> Collect like terms
3x-6+6=8-20x+6 --> Add 6 to both sides, to remove it from the right side
3x=-20x+14
3x+20x=-20x+14+20x --> Add 20x to both sides, to remove it from the left side
23x=14
--> Divide both sides by 23
x = 14/23
Answer : <em>Equation of line is</em> y=Equation of line is y=x+
Step-by-step explanation:
Theory :
Equation of line is given as y = mx + c.
Where, m is slope and c is y intercepted.
Slope of given line : y = x+1 is m=
We know that line : y = x+1 is parallel to equation of target line.
therefore, slope of target line will be .
we write equation of target line as y= x+c
Now, It is given that target line passes through point ( -5,-2)
hence, point ( -5,-2) satisfy the target line's equation.
we get,
y= x+c
-2=
-5+ c
-5= +c
c=
thus, Equation of line is y=Equation of line is y=x+