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2 years ago

Beth solved the system of equations by making a substitution for y in the second equation.

1 answer:

4 0

Short Answer: C
y = 4x - 11
3x + 5y = - 9

3x + 5(4x - 11) = - 9 Remove the brackets.
3x + 20x - 55 = - 9 <<<< Answer

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Two lines, C and D, are represented by the equations given below:

defon

Substitue y=3x+2 to the y in y=x+10.
3x+2= x+10

Subtract 2 to both sides.
3x=x+8

Subtract x to both sides.
2x=8

Divide both sides by 2
2x/2 = 8/2

You are left with x = 4

Choose one equation and replace x by 4.
y = (4) + 10
y= 14

Now, you have x = 4 and y= 14. So, your ordered pair is (4,14) because both lines pass through that point.

If you do not want to do this solution, I suggest you graph it using the slope.

8 0

3 years ago

Why is

zloy xaker [14]

Answer:

Only natural numbers (i.e., non-negative integers) can be the exponents of variables in a polynomial.

Step-by-step explanation:

The exponent of variables in a polynomial should be natural numbers ( $0$ , $1$ , $2$ , $3$ , $\dots$ .)

$\sqrt{2\, x}$ is equal to $\sqrt{2}\, x^{1/2}$ . In this expression, $x$ is the variable. Its exponent is $1/2$ , which isn't a natural number.

On the other hand, $\sqrt{2}\, x$ is equivalent to $\sqrt{2}\, x^{1}$ . The exponent of variable $x$ is $1$ , which is indeed a natural number.

$\sqrt{2\, x}$ isn't a polynomial because the exponent of variable $x$ isn't a natural number. On the other hand, $\sqrt{2}\, x$ is indeed a polynomial over the set of real numbers.

3 0

3 years ago

50 POINTS! PLEASE ASAP, BRAINLIST

Aleks04 [339]

Answer:

Quadratic equations are similar to exponential equations by having a curve in the graph. Algebraically, linear functions are polynomial functions with a highest exponent of one, exponential functions have a variable in the exponent, and quadratic functions are polynomial functions with a highest exponent of two.

6 0

2 years ago

Please help ill give brainliest, explain the answer too please

LiRa [457]

Answer:

4x^2+3x+4

Step-by-step explanation:

3x^2+2x+3+x^2+x+1=4x^2+3x+4

Please give me brainliest.

8 0

3 years ago

Find the equation of the line that passes through the points (-5,7) and (2,3)

Olegator [25]

Answer:

$y=-\frac{4}{7}x+4\frac{1}{7}$

Step-by-step explanation:

So, in order to solve this problem, I started off by drawing it out. On my graph that I have attached below, I first started out by locating the points (-5,7) and (2,3). Now, this is an optional step, but I highly encourage practicing your graphing skills by solving this problem on graph paper as well. Next, I connected the two points that I just graphed. This is the line that passes through (-5,7) and (2,3).

Now, here is where the actual solving starts. If you haven't already been taught this yet, I will introduce it to you now. I am going to find the equation of this line by filling in what I know in the equation y=mx+b, where m= the slope of the line, and b= y intercept.

Slope of the line: m= $\frac{y_{1} - y_{2} }{x_{1} - x_{2} } = \frac{7-3}{-5-2} = \frac{4}{-7}= -\frac{4}{7}$

If you haven't been taught how to find the slope of a line I recommend you find out.

Substitute the slope into the equation.

$y=-\frac{4}{7} x+b\\$

Now, we will solve for the 'b,' or y intercept.

We already have x and y values to use: (-5,7) or (2,3). I'll use x=2 and y=3 to solve for the y intercept.

$y=-\frac{4}{7} x+b\\\\3=-\frac{4}{7} *2+b\\\\3=-\frac{8}{7} +b\\b=3+\frac{8}{7} \\b=\frac{21}{7}+\frac{8}{7}=\frac{29}{7} =4\frac{1}{7} \\b=4\frac{1}{7}$

Last step: substitute the slope and y intercept into y=mx+b.

$y=mx+b\\y=-\frac{4}{7}x+4\frac{1}{7}$

That is the answer to this problem.

I hope this helps.

3 0

3 years ago