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kipiarov [429]
3 years ago
10

Calvin paid $1.79 per pound of beans both times that he went shopping for supplies for a chili cook-off. He bought 4.05 pounds o

f beans the first time and 2.78 pounds the second time. Which expression shows the total cost in dollars of the beans he bought? CLEAR

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

The cost for one pound of beans is $1.79

Calvin bought 4.05 pounds of beans the first time and 2.78 pounds the second time. The total cost for the first time is the amount of beans that he bought for the first time × the cost per pound of beans.

First time cost = 4.05×1.79 = $7.2495

The total cost for the second time is the amount of beans that he bought for the second time × the cost per pound of beans.

Second time cost = 2.78×1.79 = $4.9762

Let y represent total cost in dollars of the beans he bought. Then

y = 7.2495 + 4.9762

y = $12.2257

zmey [24]3 years ago
6 0

Answer:

Step-by-step explanation:

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Ester's choir wants to learn a new song for the school concert in 7 weeks. The song has 3016 lines. The choir learns an equal nu
andriy [413]

Hello!

We are asked to find the number of lines the choir has to learn in time for a concert.

We're given that the concert is in 7 weeks, but they learn new lines each day, so we have to convert it to days. We know that there is 7 days in a week, we would multiply 7 weeks by 7 days, which is 49 days.

Now, we would take the total number of lines, which is 3016, and divide that by 49 days.

3016 lines / 49 days ≈ 61.55 lines/day

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3 years ago
The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

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Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

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6 0
2 years ago
Determine by checking the group axiom (Associativity) whether this set is a group:
slavikrds [6]

Let x, y, z ∈ C, the set of complex numbers.

By definition of ○,

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… = x + y + z - 4i

and

x ○ (y ○ z) = x ○ (y + z - 2i)

… = x + (y + z - 2i) - 2i

… = x + y + z - 4i

so (x ○ y) ○ z = x ○ (y ○ z), which means ○ is indeed associative under C.

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Write the equation in exponential form. Log 4 1/16 =-2
steposvetlana [31]

Answer:

see explanation

Step-by-step explanation:

Using the rule of logarithms

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3 years ago
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