20,0000000000000000000000 I can’t help with this I dropped out of school
<span>The two points that are most distant from (-1,0) are
exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3)
approximately (0.3333333, 1.885618) and (0.3333333, -1.885618)
Rewriting to express Y as a function of X, we get
4x^2 + y^2 = 4
y^2 = 4 - 4x^2
y = +/- sqrt(4 - 4x^2)
So that indicates that the range of values for X is -1 to 1.
Also the range of values for Y is from -2 to 2.
Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis.
So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So
y = sqrt(4-4x^2)
distance is
sqrt((x + 1)^2 + sqrt(4-4x^2)^2)
=sqrt(x^2 + 2x + 1 + 4 - 4x^2)
=sqrt(-3x^2 + 2x + 5)
And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving
-3x^2 + 2x + 5
Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative.
d = -3x^2 + 2x + 5
d' = -6x + 2
And set d' to 0 and solve for x, so
0 = -6x + 2
-2 = -6x
1/3 = x
So the furthest point will be where X = 1/3. Calculate those points using (1) above.
y = +/- sqrt(4 - 4x^2)
y = +/- sqrt(4 - 4(1/3)^2)
y = +/- sqrt(4 - 4(1/9))
y = +/- sqrt(4 - 4/9)
y = +/- sqrt(3 5/9)
y = +/- sqrt(32)/sqrt(9)
y = +/- 4sqrt(2)/3
y is approximately +/- 1.885618</span>
The equation of line parallel to given line is: y=4x-31
Step-by-step explanation:
Given equation of line is:
The equation of line is in slope-intercept form so the co-efficient of x is the slope of the line.
Let m1 be the slope of the given line
then
m1 = 4
Let m2 be the line that is parallel to given line
As we know that the slopes of parallel lines is equal so
m1=m2 = 4
The slope-intercept form of equation of line is:
Putting the value of slope
to find the value of b, putting (5,-11) in the equation
Putting the value of b
Hence,
The equation of line parallel to given line is: y=4x-31
Keywords: Equation of line, slope
The surface area of square pyramid is the sum of the area of all its sides.
If l is the slant height and base is s each then surface area of pyramid is given by:
Surface area = s2+2xsx l
From the given figure in the question:
S=6 cm ,l= 8cm.
Substituting these values in surface area formula we have:
Surface area = 62+2x6x8
Surface area = 36+96
Surface area =132cm2
Log of 0 or <0 does not exist
so x + 6 must be > 0
so the domain is (-6, +infinity)
or x > -6
