Hello!
We are asked to find the number of lines the choir has to learn in time for a concert.
We're given that the concert is in 7 weeks, but they learn new lines each day, so we have to convert it to days. We know that there is 7 days in a week, we would multiply 7 weeks by 7 days, which is 49 days.
Now, we would take the total number of lines, which is 3016, and divide that by 49 days.
3016 lines / 49 days ≈ 61.55 lines/day
Since this is a real-world situation, we should round our answer is to nearest whole number, which would be 62 lines/day.
Therefore, Ester's choir needs to learn about 62 lines per day in time for the concert.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.
<h3>What is an area bounded by the curve?</h3>
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0
The intersection points will be
y₁ = y₂
4 - 4x² = 0
x = ±1
Then the area bounded by the curves will be
![\rm Area = \int _{-1}^1 (y_1- y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \](https://tex.z-dn.net/?f=%5Crm%20Area%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%28y_1-%20%20y_2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%284%20-%204x%5E2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cleft%20%5B%204x%20%20-%20%5Cdfrac%7B4x%5E3%7D%7B3%7D%20%5Cright%20%5D_%7B-1%7D%5E1%5C%5C%5C%5CArea%20%3D%204%20%5Cleft%20%28%201%20%2B%201%20%5Cright%20%29%20-%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cleft%20%28%201%5E3%20-%20%28-1%29%5E3%20%5Cright%20%29%5C%5C%5C%5CArea%20%3D%208%20-%20%5Cdfrac%7B8%7D%7B3%7D%5C%5C%5C%5CArea%20%3D%20%5Cdfrac%7B16%7D%7B3%7D%20%3D%205.333%20%5C)
More about the area bounded by the curve link is given below.
brainly.com/question/24563834
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Let x, y, z ∈ C, the set of complex numbers.
By definition of ○,
(x ○ y) ○ z = (x + y - 2i) ○ z
… = (x + y - 2i) + z - 2i
… = x + y + z - 4i
and
x ○ (y ○ z) = x ○ (y + z - 2i)
… = x + (y + z - 2i) - 2i
… = x + y + z - 4i
so (x ○ y) ○ z = x ○ (y ○ z), which means ○ is indeed associative under C.
Answer:
see explanation
Step-by-step explanation:
Using the rule of logarithms
•
x = n ⇔ x = 
Hence
with b = 4 and n = - 2
= - 2, then
=
← in exponential form