What is the slope of a line parallel to line B? -1/3 2/5 5/2 5/3

3. Jim invests $3500, compounded annually at 12% for 3 years. What is the total

irga5000 [103]

Answer:

None of the above, it should be $4760

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 12%/100 = 0.12 per year,

then, solving our equation

I = 3500 × 0.12 × 3 = 1260

I = $ 1,260.00

The simple interest accumulated

on a principal of $ 3,500.00

at a rate of 12% per year

for 3 years is $ 1,260.00

3 0

2 years ago

Solve. -6<3n+9<21 Thanks!

almond37 [142]

Answer:

the answer you are looking for is -5<n<4

5 0

2 years ago

Read 2 more answers

Is 432 divisible by 9 I’m looking for the estimate 432 divided by 9

Monica [59]

Answer:

Yes (432 = 9 x48).

Step-by-step explanation:

The trick you need to know is the theorem that says that if the digits in a number add up to a multiple of 9, then the number itself is divisible by 9.

So we go 4+3+2 = 9.

So as this sum of 9 is divisible by 9, it means 432 is also divisible by 9.

If you want to work out the actual answer of 432 divided by 9, you can estimate it by doing 450 ÷ 9 = 50. Then see that 432 is 18 less than 450. And 18 = 2x9. So the answer to the division is 50-2 = 48.

5 0

3 years ago

144

ahrayia [7]

Answer:

a³b < 0

Step-by-step explanation:

If a > 0 then a³ > 0

and b < 0

then

a³b → + × - → -

that is a³b < 0

8 0

2 years ago

What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir

I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0

2 years ago