Answer:
6 square root of 2
Step-by-step explanation:
sin theta = opposite / hypotenuse
sin 45 = 6/x
Multiply by x
x sin 45 = 6
Divide by sin 45
x sin 45/ sin 45 = 6 / sin 45
x = 6/ sin 45
x = 6/ (1/sqrt(2))
x = 6 sqrt(2)
Let the number be n
Part A- 2/3 + n = 2n+3
Part B- n= 2/3 -3
n= 2-9 / 3
n= -7/3 =-2.33
V = L * W * H
V = (1/2)(1/4)(2/3)
V = (1 * 1 * 2) / (2 * 4 * 3)
V = 2/24 reduces to 1/12 m <===
Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."
2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."
54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.
Her teacher would be 42. you would take 14 * 3 and get the teachers age.
