How to write unit form for (2 tens 1 one) x 10

1 answer:

3 0

Numbers are arranged by their place values. Place values give a quantity of value to a certain digit in a number. Given a number, the rightmost number is the ones place, followed by the tens place, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, as so on and so forth. The place value of a certain digit is 10 times bigger than its adjacent digit to the right.

So for this problem, all you have to do is multiply the number of units of each place value, then multiple them all by 10.

(2(10) + 1(1))×10
21 × 10 = 210

Therefore, the number is equivalent and written as 210.

You might be interested in

The expression P(4, 3) is equal to:<br> -3!<br> -4!<br> - 1

nexus9112 [7]

Answer:

$P(4,3) = 4!$

Step-by-step explanation:

Given

P(4,3)

Required

Solve

Using permutation formula;

$P(n,r) = \frac{n!}{(n-r)!}$

This implies that

$P(4,3) = \frac{4!}{(4-3)!}$

$P(4,3) = \frac{4!}{(1)!}$

$P(4,3) = \frac{4!}{1!}$

$P(4,3) = \frac{4!}{1}$

$P(4,3) = 4!$

6 0

3 years ago

3w-4z=8

Nezavi [6.7K]

W=0
Z=-2
Is there a need for explanation?

8 0

3 years ago

4. A statistician working for the National Basketball Association supplies the television announcers with interesting statistics

Sonbull [250]

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: $p=\dfrac{300}{375}=0.8$

Critical z-value for 90% confidence: z* = 1.645

Margin of error = $z^*\sqrt{\dfrac{(1-p)p}{n}}$

The margin of error in a 90% confidence interval estimate of p $=1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038$