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Kitty [74]
4 years ago
10

Write in expanded form. Use parentheses to indicate multiplication. (2r) 5

Mathematics
2 answers:
Crank4 years ago
8 0

If I assume correctly, the eqaution you ment to write is (2r)^5. If I am correct the answer your looking for is (2r)(2r)(2r)(2r)(2r) Hope this help ;-)

cricket20 [7]4 years ago
6 0
2 x 5 x r will give you this as well as 10r
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If the side of a rectangular prism is doubled, how would this affect the area? How about the volume?
professor190 [17]

Answer:

Step-by-step explanation:

The area will be increased by 4 times  and volume will be increased by 8 times

Area of rectangular prism = 2 (lb+bh +hl)

When sides are doubled, Area = 2 (2l * 2b +2b *2h + 2h*2l)

                                                     = 4 * 2 (lb+bh +hl)

Volume  of rectangular prism = lbh

When sides are doubled,  Volume = 2l * 2h * 2b = 8 lbh

6 0
3 years ago
PLEASE HELP IM DESPERATE precalculus. also 50 points!! please god help
kompoz [17]

Answer:

For B thru F these options will vary but here how you do it

B. Step 1 Draw the 4 Quadrants.

Then Draw the Triangle in the lower right quadrant which we call quadrant 4. Label the X axis as Adjacent and positive. Label the Y axis as Opposite and negative. Label the Slanted side as the hypotune and AS POSITVE SINCE HYPOTENUSE IS ALWAYS POSITIVE.

FOR C. IN QUADRANT 2, PLOT A POINT AT 0,12 AND AT (-5,0). CONNECT THE DOTS AND IT FORMS A TRIANGLE. Label the X axis as adjacent and negative and the y axis as positve and opposite and label the slanted side hypotunese and positive.

FOR D Draw a straight line along the x axis then draw a slanted line passing through (5,-1). In between them put the theta symbol in there.

The labeling is the same for C.

For E. Since tan must be positve and secant must be positve, our triangle must be in the 1st Quadrant. Draw any right triangle as long it is in the first quadrant

The x axis is adjacent and positve. The y axis is opposite and positve. The hypotenuse is the slanted side and it is positve.

For F. Since sin is negative and cos is positve the triangle is in the 4th quadrant. Draw any triangle in the 4th quadrant and the labeling is the same for Problem B.

2. We can find the sec of cos by flipping cosine.

\cos( \frac{x}{y} )  =  \sec( \frac{y}{x} )

\cos( \frac{1}{2} )  =  \sec(2 )

Sec is 2.

To find the cotangent, first let find the sin then tan.

We can use the identity

\cos( {theta}^{2} )  +  \sin( {theta}^{2} )  = 1

Let plug in the number

\cos( \frac{ {1}^{2} }{{2}^{2} } )  +  \sin(x {}^{2} )  = 1

\cos( \frac{1}{4} )  +  \sin(x {}^{2} )  = 1

\sin(x {}^{2} )  =   1 -  \frac{1}{4}

\sin(x {}^{2} )  =  \frac{3}{4}

\sin(x)  =  \frac{ \sqrt{3} }{ \sqrt{4} }

\sin(x)  =  \frac{ \sqrt{3} }{2}

Since sin is negative, sin x=

-  \frac{ \sqrt{3} }{2}

Now let apply the formula

\frac{ \sin(x) }{ \cos(x) }  =  \tan(x)

\frac{ \frac{ -  \sqrt{3} }{2} }{ \frac{1}{2} }  =  \tan(x)

-  \sqrt{3}

Now let find cotangent we can the reciprocal of

tan.

\tan=  -  \sqrt{3}

\cot =   - \frac{1}{ \sqrt{3} }

Rationalize denominator

\frac{ - 1}{ \sqrt{3} }  \times   \frac{ \sqrt{3} }{ \sqrt{3} }  =  \frac{ \sqrt -{ 3} }{3}

cotangent equal

-  \frac{ \sqrt{ 3} }{3}

4 0
3 years ago
What is equivelant to 6 divided by 27
Sholpan [36]
The fractions that's equivalent to 6/27 is 2/9
7 0
3 years ago
Read 2 more answers
The measure of an angle is 28.1°what is the measure of its complementary angle
Korvikt [17]

Answer:

Step-by-step explanation:

in complementary angle sum of two angle is always 90 degree.so,

let another be x

x+28.1=90

x=90-28.1

x=61.9

therefore another angle is 61.9 degree.

7 0
3 years ago
A pair of shoes is on sale for 15% off. With this discount, customers will save $9 if they buy the shoes. Part AIn this situatio
In-s [12.5K]

Answer:

(b)The original price of the shoes is $60.

Explanation:

Part A

In this situation:

• 15% is the PERCENT

,

• $9 is the PART

,

• The original price is the WHOLE.

Part B

If 15% is taken off, the customer will save $9.

This means that 15% of the original price = $9.

Let the original price=p

\begin{gathered} 15\%\text{ of p=9} \\ \frac{15}{100}p=9 \\ 15p=900 \\ p=\frac{900}{15} \\ p=60 \end{gathered}

The original price of the shoes is $60.

8 0
2 years ago
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