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4 years ago

Write in expanded form. Use parentheses to indicate multiplication. (2r) 5

2 answers:

Crank4 years ago

8 0

If I assume correctly, the eqaution you ment to write is (2r)^5. If I am correct the answer your looking for is (2r)(2r)(2r)(2r)(2r) Hope this help ;-)

cricket20 [7]4 years ago

6 0

2 x 5 x r will give you this as well as 10r

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jeyben [28]

Answer:

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Step-by-step explanation:

The diagonals of a parallelogram bisect each other, then

RV = $\frac{1}{2}$ RT = $\frac{1}{2}$ × 36 = 18

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3 years ago

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antoniya [11.8K]

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Step-by-step explanation:

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1 year ago

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3 years ago

Simplify the expression <br> -1/8-2/7

SpyIntel [72]

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4 0

3 years ago

Read 2 more answers

Find all zeros x^3+2x^2+4x+21

dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

$\frac{x^3+2x^2+4x+21}{x+3}$ = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± $\sqrt{1-28}$ ) / 2 = (1 ± 3i $\sqrt{3}$ ) / 2

x = $\frac{1}{2}$ ± $\frac{3i\sqrt{3} }{2}$

zeros are x = - 3, x = $\frac{1}{2}$ ± $\frac{3i\sqrt{3} }{2}$

5 0

3 years ago