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2 years ago

How do I solve 4.6x^2 + 3.2x - 4x + 2.7x^2 - x

1 answer:

4 0

4.6x^2+3.2-4x+2.7x^2-x=4.6x^2+3.2x+-4x+2.7x^2+-xCombine like terms:4.6x^2+3.2x+-4x+2.7x^2+-x=(4.6x^2+2.7x^2)+(3.2x+-4x+-x)=7.3x^2+-1.8xAnswer:7.3x^2-1.8x

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How to do a line plot to the nearest fourth inch

Shalnov [3]

Just count, its really simple...its hard to explain using a keyboard tho...sorry i wasnt much help

6 0

3 years ago

Which situation represents a proportional relationship?

Natalka [10]

Answer:

B) Jack biked 5 miles in 25 minutes and 8 miles in 40 minutes.

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y=kx$

The ratio between the two variables is a constant called constant of proportionality k

$k=y/x$

Verify each case

A) Julie sold 4 necklaces for $12 and 9 necklaces for $25.

$\frac{4}{12}=\frac{9}{25}$

Multiply in cross

$4(25)=9(12)\\100\neq108$

Is not true

therefore

The situation not represent a proportional relationship

B) Jack biked 5 miles in 25 minutes and 8 miles in 40 minutes.

$\frac{5}{25}=\frac{8}{40}$

Multiply in cross

$5(40)=8(25)\\200=200$

Is true

therefore

The situation represent a proportional relationship

C) Larry packed 24 apples in 6 boxes and 46 apples in 9 boxes

$\frac{24}{6}=\frac{46}{9}$

Multiply in cross

$24(9)=46(6)\\216\neq276$

Is not true

therefore

The situation not represent a proportional relationship

D) Allie put 14 pieces of candy in 2 bags and 30 pieces of candy in 4 bags

$\frac{14}{2}=\frac{30}{4}$

Multiply in cross

$14(4)=30(2)\\56\neq60$

Is not true

therefore

The situation not represent a proportional relationship

7 0

3 years ago

A scale on a blue print drawing of a house shows that 10 1010 centimeters represents 2 22 meters. What number of actual meters a

Ivenika [448]

Answer:

On Blue print 18 centimeters represents 3.6 meters.

Step-by-step explanation:

Given:

Scale is 10 cm = 2 m

We need to find the number of actual meters are represented by 18 1818 centimeters on the blue print.

Solution:

Now we know that;

10 cm = 2 m

so 1 cm = Number of meters in 1 cm.

By using Unitary method we get;

Number of meters in 1 cm = $\frac{2}{10}=0.2\ m$

Now we know that;

1 cm = 0.2 m

18 cm = Number of meters in 18 cm.

Again by using Unitary method we get;

Number of meters in 18 cm = $0.2\times 18 = 3.6\ m$

Hence On Blue print 18 centimeters represents 3.6 meters.

7 0

2 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

After studying the diagram shown, Michael makes the following conclusions:

inn [45]

Answer:

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

$(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\$

Now Add DG² and AG² we get

$(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}$

Which is also called as Pythagoras theorem i.e

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

3 0

3 years ago