Answer:
If x is the distance from centre fo the circle, with radius 25cm, to its intersection point with the common chord, x²+24²=25² =>x=7cm.
Distance from this intersecting point to the centre of the other circle=39–7=32cm
Ratio of the sides of the right triangle thus formed is 24:32=3:4. Since 3:4:5 is the basic pythagorean triplet, the radius of the other circle=5*24/3=40cm.
Aliter: radius of the other circle=√32²+24²= 40cm.
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Answer:
4x^2 – 25
Step-by-step explanation:
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Answer:
150cm
Step-by-step explanation:
0.4*100-5=35
(35+40)*2=150
Steps to solve:
8j - k + 14; j = 0.25 and k = 1
~Substitute
8(0.25) - (1) + 14
~Simplify
2 - 1 + 14
~Subtract
1 + 14
~Add
15
Best of Luck!
Answer:
Yes, the area is 49 cm^2
Step-by-step explanation: