Answer:
50
Step-by-step explanation:
[15 ÷ 5 • 3 + (2³ – 3)] + [4 • (36 – 3³)]
[3 × 3 + (8 - 3)] + [4 × (36 - 27)]
(9 + 5) + (4 × 9)
14 + 36
50
Answer:
Probability that the sample average is at most 3.00 = 0.98030
Probability that the sample average is between 2.65 and 3.00 = 0.4803
Step-by-step explanation:
We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.
Also, a random sample of 25 specimens is selected.
Let X bar = Sample average sediment density
The z score probability distribution for sample average is given by;
Z = 
~ N(0,1)
where, 
= population mean = 2.65
= standard deviation = 0.85
n = sample size = 25
(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)
P(X bar <= 3) = P( <= 
) = P(Z <= 2.06) = 0.98030
(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)
P(X bar < 3) = P( < ) = P(Z < 2.06) = 0.98030
P(X bar <= 2.65) = P( <= 
) = P(Z <= 0) = 0.5
Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .
Answer:
Step-by-step explanation:
<h3>3
Answers:</h3>
- B) Mean
- C) Mean absolute deviation
- E) Mode
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Explanation:
The box plot, aka "box-and-whisker plot", visually represents five things. These things are:
- Minimum
- Q1 = first quartile
- Median (sometimes referred to as Q2 or second quartile)
- Q3 = third quartile
- Maximum
This list of five items is known as the five number summary.
The min is the tip of the left most whisker, assuming there aren't any small outliers. The max is the opposite side, being the tip of the right most whisker (assuming no large outliers). If there are any outliers, then they'll be shown as "island" dots on their own separated from the main box plot. The left and right edges of the box are Q1 and Q3 respectively. The median is the vertical line inside the box. The vertical line does not have to be at the midpoint of the left and right edges of the box. It simply needs to be somewhere in the box.
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Since the box plot lets us know the min and max, we can compute the range because
range = max - min
and we can also calculate the interquartile range (IQR) because
IQR = Q3 - Q1
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So to summarize so far, the five number summary is visually represented as the box plot. The range and IQR can be computed using items from the five number summary.
We cannot compute the mean because we would need the actual data set of values, rather than the summary data. The same goes for the mean absolute deviation (MAD) and the mode. Since your teacher is looking for things that cannot be determined from a box plot, we'll go for answers B, C and E.
In other words, we rule out choices A, D, and F because we can compute or determine those values from a box plot.
Answer:
Therefore the probability that the marble is blue or even numbered is 
Step-by-step explanation:
Probability: The ratio of favorable outcomes to the total outcomes.
It is denoted by P.
Given that a jar contains 8 red marbles and 7 blue marbles.
Total number of marbles = (8+7) = 15
Let A = Event of getting a blue marble
B= Event of getting of even marble.
Even number blue marbles are 2, 4,6
Even number red marbles are 2, 4,6,8
The number of even marbles are =(3+4)=7
The probability of getting a blue marble is P(A)
The probability of getting a even marble is P(B)
The probability of getting a even numbered blue marble P(A∩B)
P(blue marble or even- numbered)
=P(A∪B)
=P(A)+P(B)-P(A∩B)
Therefore the probability that the marble is blue or even numbered is
