I'm pretty sure its B but I would double check before you put the answer in :)
A=pi(radius^2)
630/3.14=200.64
radius=14.16 feet
C=2(pi)(radius)
=3.14(2)(14.16)
=6.28(14.16)
C=88.92
88.92<100
Yes! He has enough fencing to enclose the circular area.
Answer:
x = 10
Step-by-step explanation:
if there 2 same triangle then they are right triangle
By using Pythagorean theorem for 1 of right triangle, we have
=
+ ![(\frac{x}{2}) ^{2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bx%7D%7B2%7D%29%20%5E%7B2%7D)
74 = 49 + ![\frac{x^{2}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%7D)
74 - 49 = ![\frac{x^{2}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%7D)
25 = ![\frac{x^{2}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%7D)
therefore, x =
=
= 10
bearing in mind that the centroid in a triangle cuts each of the three medians in a 2:1 ratio.
since we know that A C = 12, let's split it in a 2:1 ratio then, cleary from the picture the larger is F C, so F C : A F is on a 2:1 ratio.
![\bf A C=A F+F C\qquad \qquad \cfrac{F C}{A F}=\cfrac{2}{1}\qquad \qquad \cfrac{2\cdot \frac{12}{2+1}}{1\cdot \frac{12}{2+1}}\implies \cfrac{2\cdot 4}{1\cdot 4}\implies \cfrac{8}{4}](https://tex.z-dn.net/?f=%5Cbf%20A%20C%3DA%20F%2BF%20C%5Cqquad%20%5Cqquad%20%5Ccfrac%7BF%20C%7D%7BA%20F%7D%3D%5Ccfrac%7B2%7D%7B1%7D%5Cqquad%20%5Cqquad%20%5Ccfrac%7B2%5Ccdot%20%5Cfrac%7B12%7D%7B2%2B1%7D%7D%7B1%5Ccdot%20%5Cfrac%7B12%7D%7B2%2B1%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%204%7D%7B1%5Ccdot%204%7D%5Cimplies%20%5Ccfrac%7B8%7D%7B4%7D)
Budget ≤ 1250 - 439
m = $811